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Explain the arguments given in favour of strong Centre in the Constituent Assembly.
Concept: The Powers of the State
Match the following:
| Column-I (Leaders) |
Column-II - (Role in the Constituent Assembly) |
||
| A. | Jawaharlal Nehru | i. | President of the Constituent Assembly |
| B. | B.R. Ambedkar | ii. | Constitutional Advisor |
| C. | Rajendra Prasad | iii. | Chairman of the Drafting Committee |
| D. | B.N. Rau | iv. | Worked on the 'Objective Resolution' |
Concept: A Tumultuous Time
Consider the given statements regarding Constituent Assembly and select the correct from the following options:
- Motilal Nehru moved resolution of National flag in the Constituent Assembly.
- G.B. Pant was the Legal Advisor.
- Sardar Patel was the Constitutional Advisor.
- K.M. Munshi was called as Frontier Gandhi.
Concept: A Tumultuous Time
"One of the topics most vigorously debated in the Constituent Assembly was the respective rights of the Central and State governments." Analyse the statement with supporting arguments.
Concept: The Powers of the State
Let A = {1, 2, 3,......, 9} and R be the relation in A × A defined by (a, b) R (c, d) if a + d = b + c for (a, b), (c, d) in A × A. Prove that R is an equivalence relation. Also, obtain the equivalence class [(2, 5)].
Concept: Types of Relations
Let f : N→N be a function defined as f(x)=`9x^2`+6x−5. Show that f : N→S, where S is the range of f, is invertible. Find the inverse of f and hence find `f^-1`(43) and` f^−1`(163).
Concept: Inverse of a Function
Let N denote the set of all natural numbers and R be the relation on N × N defined by (a, b) R (c, d) if ad (b + c) = bc (a + d). Show that R is an equivalence relation.
Concept: Types of Relations
If R=[(x, y) : x+2y=8] is a relation on N, write the range of R.
Concept: Types of Relations
If the function f : R → R be given by f[x] = x2 + 2 and g : R → R be given by `g(x)=x/(x−1)` , x≠1, find fog and gof and hence find fog (2) and gof (−3).
Concept: Inverse of a Function
If `f(x) = (4x + 3)/(6x - 4), x ≠ 2/3`, show that fof (x) = x for all `x ≠ 2/3`. Also, find the inverse of f.
Concept: Types of Relations
The function f(x) = [x], where [x] denotes the greatest integer less than or equal to x; is continuous at ______.
Concept: Types of Functions
Read the following passage:
|
An organization conducted bike race under two different categories – Boys and Girls. There were 28 participants in all. Among all of them, finally three from category 1 and two from category 2 were selected for the final race. Ravi forms two sets B and G with these participants for his college project. |
Based on the above information, answer the following questions:
- How many relations are possible from B to G? (1)
- Among all the possible relations from B to G, how many functions can be formed from B to G? (1)
- Let R : B `rightarrow` B be defined by R = {(x, y) : x and y are students of the same sex}. Check if R is an equivalence relation. (2)
OR
A function f : B `rightarrow` G be defined by f = {(b1, g1), (b2, g2), (b3, g1)}. Check if f is bijective. Justify your answer. (2)
Concept: Types of Relations
Prove that `cot^(-1)((sqrt(1+sinx)+sqrt(1-sinx))/(sqrt(1+sinx)-sqrt(1-sinx)))=x/2;x in (0,pi/4) `
Concept: Properties of Inverse Trigonometric Functions
Prove that:
`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`
Concept: Properties of Inverse Trigonometric Functions
Solve for x:
`2tan^(-1)(cosx)=tan^(-1)(2"cosec" x)`
Concept: Inverse Trigonometric Functions (Simplification and Examples)
If a line makes angles 90°, 60° and θ with x, y and z-axis respectively, where θ is acute, then find θ.
Concept: Properties of Inverse Trigonometric Functions
If sin [cot−1 (x+1)] = cos(tan−1x), then find x.
Concept: Inverse Trigonometric Functions (Simplification and Examples)
If (tan−1x)2 + (cot−1x)2 = 5π2/8, then find x.
Concept: Inverse Trigonometric Functions (Simplification and Examples)
If tan-1x+tan-1y=π/4,xy<1, then write the value of x+y+xy.
Concept: Inverse Trigonometric Functions (Simplification and Examples)
Prove that
`tan^(-1) [(sqrt(1+x)-sqrt(1-x))/(sqrt(1+x)+sqrt(1-x))]=pi/4-1/2 cos^(-1)x,-1/sqrt2<=x<=1`
Concept: Inverse Trigonometric Functions (Simplification and Examples)

