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Revision: Mathematics >> Integrals CUET (UG) Integrals

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Definitions [11]

Definition: Indefinite Integral

The collection of all anti-derivatives of a function is called its indefinite integral.

If \[ F'(x) = f(x), \]

then \[ \int f(x)\, dx = F(x) + C \]

Here: f(x) = integrand, dx = variable of integration, C = constant of integration.

Definition: Definite Integral

A definite integral is connected with finding the area under a curve over a given interval. The chapter introduction presents area as one of the central motivating ideas behind integral calculus.

\[\int_{a}^{b} f(x) dx\]
where aa and bb are fixed limits of integration.
Definition: Antiderivative

If the derivative of a function F(x) is f(x), then F(x) is called an antiderivative or integral of f(x). The set of all such antiderivatives is written as:

\[\int f(x) dx = F(x) + C\]

where C is an arbitrary constant called the constant of integration.

Definition: Integration by Substitution

Integration by substitution is a method in which we replace a part of the integral by a new variable to simplify the integration.

General Formula:

If \[x = g(t), \ dx = g'(t) dt\] then \[\int f(x) dx = \int f(g(t))g'(t) dt\]

Proper and Improper Function

Proper Rational Function

A rational function \[ \frac{P(x)}{Q(x)} \] is called proper if \[ \deg P(x) < \deg Q(x). \]

Improper Rational Function

It is called improper if \[ \deg P(x) \geq \deg Q(x). \]

An improper rational function must first be reduced to a proper rational function by long division.

Definition: Rational Function

A rational function is a function of the form \[ \frac{P(x)}{Q(x)} \] where P(x) and Q(x) are polynomials and Q(x) \neq 0.

Definition: Integration Using Partial Fractions

Integration by partial fractions is a method used to integrate rational functions, that is, functions of the form

\[\frac{p(x)}{q(x)}\], where both numerator and denominator are polynomials.

A proper rational function can be expressed as a sum of simpler rational functions called partial fractions.

Definition: Integration by Parts

Integration by parts is a method of integration based on the product rule of differentiation.

If u and v are differentiable functions, then \[ \boxed{\int u\, dv = uv - \int v\, du} \]

For a product f(x)g(x), \[ \boxed{\int f(x)g(x)\, dx = f(x)\int g(x)\, dx - \int\left[f'(x)\int g(x)\, dx\right]dx} \]

Definition: Integration using Trigonometric Identities

Integration using trigonometric identities means converting a trigonometric expression into an easier form with the help of standard identities before integrating.

Definition: Definite integral

A definite integral represents the value of a function accumulated between two limits.
It can also be interpreted geometrically as the net area between the graph of y = f(x) and the x-axis from x = a to x = b.

Definition: Area Function

If a function f is continuous on an interval, the area function is defined by

\[A(x) = \int_{a}^{x} f(t) \, dt\]

This means that A(x) gives the area accumulated from x = a to a variable point x.

Formulae [2]

Formula: Integral Formulas
No. Derivatives Integrals (Anti-derivatives)
(i) \[\frac{d}{dx} \left( \frac{x^{n+1}}{n+1} \right) = x^n\]; \[\int x^n dx = \frac{x^{n+1}}{n+1} + \text{C}, n \neq -1\]
  \[\frac{d}{dx} (x) = 1\]; \[\int dx = x + \text{C}\]
(ii) \[\frac{d}{dx} (\sin x) = \cos x\]; \[\int \cos x dx = \sin x + \text{C}\]
(iii) \[\frac{d}{dx} (-\cos x) = \sin x\]; \[\int \sin x dx = -\cos x + \text{C}\]
(iv) \[\frac{d}{dx} (\tan x) = \sec^2 x\]; \[\int \sec^2 x dx = \tan x + \text{C}\]
(v) \[\frac{d}{dx} (-\cot x) = \text{cosec}^2 x\]; \[\int \text{cosec}^2 x dx = -\cot x + \text{C}\]
(vi) \[\frac{d}{dx} (\sec x) = \sec x \tan x\]; \[\int \sec x \tan x dx = \sec x + \text{C}\]
(vii) \[\frac{d}{dx} (-\text{cosec} x) = \text{cosec} x \cot x\]; \[\int \text{cosec} x \cot x dx = -\text{cosec} x + \text{C}\]
(viii) \[\frac{d}{dx} (\sin^{-1} x) = \frac{1}{\sqrt{1-x^2}}\]; \[\int \frac{dx}{\sqrt{1-x^2}} = \sin^{-1} x + \text{C}\]
(ix) \[\frac{d}{dx} (-\cos^{-1} x) = \frac{1}{\sqrt{1-x^2}}\]; \[\int \frac{dx}{\sqrt{1-x^2}} = -\cos^{-1} x + \text{C}\]
(x) \[\frac{d}{dx} (\tan^{-1} x) = \frac{1}{1+x^2}\]; \[\int \frac{dx}{1+x^2} = \tan^{-1} x + \text{C}\]
(xi) \[\frac{d}{dx} (e^x) = e^x\]; \[\int e^x dx = e^x + \text{C}\]
(xii) \[\frac{d}{dx}\left(\log|x|\right)=\frac{1}{x};\] \[\int\frac{1}{x}dx=\log|x|+\mathrm{C}\]
(xiii) \[\frac{d}{dx} \left( \frac{a^x}{\log a} \right) = a^x\]; \[\int a^x dx = \frac{a^x}{\log a} + \text{C}\]
Fundamental Integration Formulae
  • \[\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left| \frac{x - a}{x + a} \right| + C\]
  • \[\int \frac{dx}{a^2 - x^2} = \frac{1}{2a} \log \left| \frac{a + x}{a - x} \right| + C\]
  • \[\int \frac{dx}{x^2 + a^2} = \frac{1}{a} \tan^{-1} \left(\frac{x}{a}\right) + C\]
  • \[\int \frac{dx}{\sqrt{x^2 - a^2}} = \log \left| x + \sqrt{x^2 - a^2} \right| + C\]
  • \[\int \frac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1} \left(\frac{x}{a}\right) + C\]
  • \[\int \frac{dx}{\sqrt{x^2 + a^2}} = \log \left| x + \sqrt{x^2 + a^2} \right| + C\]

Theorems and Laws [3]

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`

Let I = `int sqrt(a^2 - x^2) dx`

= `int sqrt(a^2 - x^2)*1 dx`

= `sqrt(a^2 - x^2)* int 1 dx - int [d/dx (sqrt(a^2 - x^2))* int 1 dx]dx`

= `sqrt(a^2 - x^2)*x - int [1/(2sqrt(a^2 - x^2))*d/dx (a^2 - x^2)*x]dx`

= `sqrt(a^2 - x^2)*x - int 1/(2sqrt(a^2 - x^2))(0 - 2x)*x  dx`

= `sqrt(a^2 - x^2)*x - int (-x)/sqrt(a^2 - x^2)*x  dx`

= `xsqrt(a^2 - x^2) - int (a^2 - x^2 - a^2)/sqrt(a^2 - x^2)dx`

= `xsqrt(a^2 - x^2) - int sqrt(a^2 - x^2)dx + a^2 int dx/sqrt(a^2 - x^2)`

= `xsqrt(a^2 - x^2) - I + a^2sin^-1(x/a) + c_1`

∴ 2I = `xsqrt(a^2 - x^2) + a^2sin^-1(x/a) + c_1`

∴ I = `x/2 sqrt(a^2 - x^2) + a^2/2 sin^-1(x/a) + c_1/2`

∴ `int sqrt(a^2 - x^2)dx = x/2 sqrt(a^2 - x^2) + a^2/2sin^-1(x/a) + c`, where `c = c_1/2`.

Theorem: First Fundamental Theorem

If f is continuous on [a, b] and

\[A(x) = \int_{a}^{x} f(t) \, dt\] 
then A'(x) = f(x) for every x in (a, b).
This means the derivative of the accumulated area
function is the original function itself.
Theorem: Second Fundamental Theorem

If f is continuous on [a, b] and F is any antiderivative of f, then

\[\int_{a}^{b} f(x) \, dx = F(b) - F(a)\]

This is the formula most often used in exams to evaluate definite integrals.

Key Points

Key Points: Introduction of Integrals
  • Primitive
    Another name for anti-derivative.
  • Indefinite Integral
    The family of all anti-derivatives of a function.
  • Definite Integral
    An integral taken between two fixed limits, commonly used to represent area or total accumulation.
  • Integral Calculus
    The branch of calculus dealing with anti-derivatives, accumulation, and areas under curves.
Key Points: Integration as an Inverse Process of Differentiation
  • Integration is the inverse process of differentiation.

  • The result of indefinite integration is called the antiderivative or primitive.

  • The indefinite integral is written as: ∫f(x) dx = F(x) + C.

  • The constant C must always be added in indefinite integrals.

Key Points: Properties of Indefinite Integrals
Property Formula
Reverse of differentiation \[\frac{d}{dx}\left(\int f(x) dx\right) = f(x)\]
Same derivative \[F'(x) = G'(x) \Rightarrow F(x) = G(x) + C\]
Sum rule \[\int (f + g)dx = \int fdx + \int gdx\]
Difference rule \[\int (f - g)dx = \int fdx - \int gdx\]
Constant multiple rule \[\int k f(x)dx = k \int f(x)dx\]
General linearity \[\int (kf \pm lg)dx = k \int fdx \pm l \int gdx\]
Key Points: Standard Substitution
  • Integration by substitution is the reverse process of the chain rule.

  • Choose the substitution so that the integral becomes simpler, not more complicated.

  • Always rewrite both the function and \(dx\) in terms of the new variable.

  • For indefinite integrals, back-substitute and add \(C\).

  • For definite integrals, limits should also be changed if the solution is continued in the new variable.

  • Trigonometric substitution is mainly used for radicals involving \(a^2-x^2\), \(x^2+a^2\), and \(x^2-a^2\).

Key Points : Partial Fractions
  • First check whether the rational function is proper or improper.

  • Use long division before decomposition if the fraction is improper.

  • Factorise the denominator completely before choosing partial fractions.

  • For each distinct linear factor, use a constant numerator such as A, B, or C.

  • For a repeated linear factor, include every power separately.

  • For an irreducible quadratic factor, use a linear numerator of the form Bx + C.

  • After decomposition, integrate each term separately using standard formulas.

Key Points: Integrals of Some Particular Functions
  • Convert the integrand into a known standard form before integrating.

  • For \[x^2 - a^2\], factorize and use partial fractions.

  • For \[x^2 + a^2\], the answer usually involves \[\tan^{-1}\].

  • For \[\sqrt{a^2 - x^2}\], the answer usually involves \[\sin^{-1}\].

  • For general quadratics, complete the square first.

  • For \[px + q\] in the numerator, relate it to the derivative of the denominator.

  • Always write the constant of integration C in the final answer.

Key Points: Integration by Parts
  • Formula:

    \[\int u dv = uv - \int v du\]
  • Choose u by LIATE

  • For log x and inverse trig, multiply by 1

  • Repeated parts may be needed for \[e^x \sin x\], \[e^x \cos x\].

Key Points: Integration Using Trigonometric Identities
  • First inspect the pattern in the integrand.

  • Do not integrate complicated trigonometric expressions directly if an identity can simplify them first.

  • After simplification, integrate term by term carefully.

  • Always add the constant of integration, \(C\).

Key Points: Definite Integrals
  • Used to find exact accumulated value over a fixed interval.

  • Written as \[\int_{a}^{b} f(x) \, dx\].

  • Evaluated using \[F(b) - F(a)\].

  • Gives a unique numerical value.

  • Represents net area geometrically.

Key Points: Fundamental Theorem of Integral Calculus
  • The theorem connects differentiation and integration.

  • If \[A(x) = \int_{a}^{x} f(t) \, dt\], then \[A'(x) = f(x)\].

  • If  F'(x) = f(x), then \[\int_{a}^{b} f(x) \, dx = F(b) - F(a)\].

  • The result is used to evaluate definite integrals quickly.

  • The function should be continuous on the interval for direct use of the theorem.

Key Points: Evaluation of Definite Integrals by Substitution
  • Look for an inner function and its derivative.

  • Choose substitution carefully.

  • If the integral is continued in the new variable, change the limits accordingly.

  • Integrate in the new variable.

  • Do not add +C in a definite integral.

  • Once the limits have been changed to the new variable, there is no need to substitute back to the original variable.
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