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Write the structure and name of monomer of Natural rubber. - Chemistry

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प्रश्न

Write the structure and name of monomer of Natural rubber.

Write the name and structure of the monomer of the following polymer:

Natural rubber

Name the monomer of natural rubber.

Give the structure of the monomer of natural rubber.

रासायनिक समीकरण/संरचनाएँ
एक शब्द/वाक्यांश उत्तर
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उत्तर

Name of monomer of natural rubber: Isoprene (2-Methyl-1, 3-butadiene)

Structure:

\[\begin{array}{cc}
\ce{CH3}\phantom{.....}\\
|\phantom{.........}\\
\ce{CH2 = C - CH = CH2} 
\end{array}\]

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Notes

Students should refer to the answer according to their questions.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Polymers - REVIEW exercises [पृष्ठ १००४]

APPEARS IN

नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 15 Polymers
REVIEW exercises | Q 15.16 (i) | पृष्ठ १००४
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 15 Polymers
REVIEW exercises | Q 15.46 (i) | पृष्ठ १०१३
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 15 Polymers
VERY SHORT ANSWER TYPE QUESTIONS | Q 6. | पृष्ठ १०१८
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 15 Polymers
SHORT ANSWER TYPE QUESTIONS | Q 4. ii. | पृष्ठ १०१९

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

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I. \[\begin{array}{cc}
\ce{-(CH2 - CH -)_{{n}}}\\
\phantom{....}|\\
\phantom{.......}\ce{C6H5}
\end{array}\]

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IV.


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\[\begin{array}{cc}
\phantom{....}\ce{O}\phantom{............}\ce{O}\phantom{...................}\ce{H}\phantom{.....}\\
\phantom{....}||\phantom{.............}||\phantom{...................}|\phantom{......}\\
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\end{array}\]


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Column I Column II
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(a) \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{....}|\\
\phantom{.......}\ce{C6H5}
\end{array}\]

(ii) Polystyrene (b) \[\begin{array}{cc}
\ce{Cl}\phantom{.......}\\
|\phantom{........}\\
\phantom{}\ce{-(CH2 - C = CH - CH2)\underset{n}{-}}
\end{array}\]
(iii) Neoprene (c) \[\begin{array}{cc}
\phantom{................................}\ce{CN}\\
\phantom{..............................}|\\
\ce{-(CH2 - CH = CH - CH2 - CH2 - CH)\underset{n}{-}}
\end{array}\]
(iv) Novolac (d) \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{.....}|\\
\phantom{.......}\ce{CN}
\end{array}\]
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\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{.....}|\\
\phantom{......}\ce{Cl}
\end{array}\]

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