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प्रश्न
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - CH - CH - CH3}\\
|\phantom{......}|\phantom{..}\\
\ce{OH}\phantom{...}\ce{OH}\phantom{}
\end{array}\]
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उत्तर
Butane-2, 3-diol
APPEARS IN
संबंधित प्रश्न
Write IUPAC name of the following compound:
Write IUPAC name of the following compound:
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - O - CH2 - CH - CH3}\\
\phantom{..........}|\\
\phantom{............}\ce{CH3}
\end{array}\]
Natalite is a mixture of
(a) diethyl ether and methanol
(b) diethyl ether and ethanol
(c) dimethyl ether and methanol
(d) dimethyl ether and ethanol
Write the structure and IUPAC name of 'methyl-n-propyl ether'.
How is phenol converted into the following?
Benzene
Write the structures of the products when Butan-2-ol reacts with SOCl2
Isopropyl alcohol on oxidation forms:
Give IUPAC names of the following compound:
\[\begin{array}{cc}
\phantom{..}\ce{H}\phantom{...}\ce{CH3}\phantom{.}\ce{H}\phantom{..}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\ce{H - C - C - C - H}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\phantom{.}\ce{H}\phantom{...}\ce{OH}\phantom{.}\ce{H}\phantom{.}\\
\end{array}\]
The IUPAC name of the ether CH2 = CH–CH2OCH3 is:
\[\ce{HC ≡ CH ->[HgSO4][H2SO4] ->[CH3MgBr][H2O] ->[PBr3]}\]
The heating of phenyl methyl ether with HI produces:
Which of the following gives a positive iodoform test?
Which of the following compounds will react with sodium hydroxide solution in water?
What happens when benzene diazonium chloride is heated with water?
Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.
| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) |  |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) |  |
| (iv) |  |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
Assertion: Phenols give o- and p-nitrophenol on nitration with conc. \[\ce{HNO3}\] and \[\ce{H2SO4}\] mixture.
Reason: –OH group in phenol is o–, p– directing.
Explain why Lewis acid is not required in bromination of phenol?
Convert the following:
Ethyl alcohol into ethyl acetate.
