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Convert the following: Ethyl alcohol into ethyl acetate.

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प्रश्न

Convert the following:

Ethyl alcohol into ethyl acetate.

अति संक्षिप्त उत्तर
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उत्तर

Ethyl alcohol reacts with acetic acid to give ethyl acetate.

\[\ce{\underset{Ethyl alcohol}{C2H5OH} + \underset{Acetic acid or Ethanoic acid}{CH3COOH} <=>[H+] \underset{ethyl acetate}{CH3COOC2H5} + H2O}\]

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संबंधित प्रश्न

Name the following compound according to the IUPAC system.

\[\begin{array}{cc}
\ce{H2C = CH - CH - CH2 - CH2 - CH3}\\
|\phantom{...............}\\
\ce{OH}\phantom{............}
\end{array}\]


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{........................}\ce{CH3}\\
\phantom{....................}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{.........}|\phantom{.........}|\\
\phantom{...}\ce{CH3}\phantom{....}\ce{OH}\phantom{....}\ce{CH3}\\
\end{array}\]


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\ce{H3C - CH - CH2 - CH - CH - CH2 - CH3}\\
|\phantom{....................}|\phantom{.........}|\phantom{.............}\\
\ce{OH}\phantom{................}\ce{OH}\phantom{...}\ce{C{_2}H5}\phantom{.........}\\
\end{array}\]


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CH3OCH2CH2Cl


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Write IUPAC name of the following

\[\begin{array}{cc}\ce{CH3-CH-CH-CH2-OH}\\|\phantom{.....}|\phantom{.......}\\\ce{OH}\phantom{..}\ce{CH3}\phantom{.....}\end{array}\]


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HBr reacts fastest with ____________.


n-Propyl alcohol and isopropyl alcohol can be chemically distinguished by which reagent?


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1-Propanol and 2-propanol can be best distinguished by:


The major product formed by the reaction:

\[\begin{array}{cc}
\ce{CH3CH-CH2Br ->[CH3O^-][CH3OH] is}\\
|\phantom{................}\\
\ce{CH3}\phantom{.............}
\end{array}\]


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\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]


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(i) (a) Hydroquinone
(ii) (b) Phenetole
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(vi) (f) Resorcinol
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Reason: –OH group in phenol is o–, p– directing.


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Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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