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प्रश्न
Why cannot aromatic primary amines be prepared by Gabriel phthalimide synthesis?
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उत्तर
Gabriel synthesis is used for the preparation of primary amines. Phthalimide, on treatment with ethanolic potassium hydroxide, forms potassium salt of phthalimide, which on heating with alkyl halide followed by alkaline hydrolysis produces the corresponding primary amine. Aromatic primary amines cannot be prepared by this method because aryl halides do not undergo nucleophilic substitution with the anion formed by phthalimide.



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संबंधित प्रश्न
Write a short note on the following:
Hoffmann’s bromamide reaction
Accomplish the following conversion:
Nitrobenzene to benzoic acid
Give the structures of A, B and C in the following reactions :

Choose the most correct option.
Which of the following compounds will dissolve in aqueous NaOH after undergoing reaction with Hinsberg reagent?
Write reactions to bring about the following conversions.
Acetamide to methylamine
Explain the following reaction with a suitable example.
Hofmann elimination reaction
Identify compound 'B' in following series of reactions?
\[\ce{Acetonitrile ->[Na/alcohol] A ->[NaNO2/dil.HCI] B}\]

Identify the major product (B).
Which of the following compounds is obtained when quaternary ammonium hydroxide is strongly heated?
Nitro compounds are reduced by iron scrap and hydrochloric acid to yield one of the following compounds:
Benzylamine may be alkylated as shown in the following equation:
\[\ce{C6H5CH2NH2 + R - X -> C6H5CH2NHR}\]
Which of the following alkylhalides is best suited for this reaction through SN1 mechanism?
Which of the following reagents would not be a good choice for reducing an aryl nitro compound to an amine?
The reagents that can be used to convert benzenediazonium chloride to benzene are:
(i) \[\ce{SnCl2/HCl}\]
(ii) \[\ce{CH3CH2OH}\]
(iii) \[\ce{H3PO2}\]
(iv) \[\ce{LiAlH4}\]
Write following conversions:
acetanilide `->` p-nitroaniline
How will you bring out the following conversion?

How will you carry out the following conversion?

Assertion: Hoffmann’s bromamide reaction is given by primary amines.
Reason: Primary amines are more basic than secondary amines.
A primary amine is formed by an amide on treatment with bromine and alkali. The primary amine has
C6H5CONHCH3 can be converted into C6H5CH2NHCH3 by:-
Identify A and B in the following reaction.
\[\ce{C6H5CH2Br ->[Alco.][KCN] A ->[Na/Ethanol][reduction] B}\]
