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What is the Frequency of Oscillation of a Simple Pendulum Mounted in a Cabin that is Freely Falling Under Gravity?

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प्रश्न

Answer the following questions:

What is the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity?

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उत्तर १

When a simple pendulum mounted in a cabin falls freely under gravity, its acceleration is zero. Hence the frequency of oscillation of this simple pendulum is zero.

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उत्तर २

During free fall of the cabin, the acceleration due to gravity is zero. Therefore, the frequency of oscillations is also zero i.e., the pendulum will not vibrate at all.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Oscillations - Exercises [पृष्ठ ३६१]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 11
अध्याय 13 Oscillations
Exercises | Q 16.4 | पृष्ठ ३६१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

The period of a conical pendulum in terms of its length (l), semi-vertical angle (θ) and acceleration due to gravity (g) is ______.


If the metal bob of a simple pendulum is replaced by a wooden bob of the same size, then its time period will.....................

  1. increase
  2. remain same
  3. decrease
  4. first increase and then decrease.

When the length of a simple pendulum is decreased by 20 cm, the period changes by 10%. Find the original length of the pendulum.


A spring having with a spring constant 1200 N m–1 is mounted on a horizontal table as shown in Fig. A mass of 3 kg is attached to the free end of the spring. The mass is then pulled sideways to a distance of 2.0 cm and released.

Determine (i) the frequency of oscillations, (ii) maximum acceleration of the mass, and (iii) the maximum speed of the mass.


let us take the position of mass when the spring is unstretched as x = 0, and the direction from left to right as the positive direction of the x-axis. Give as a function of time t for the oscillating mass if at the moment we start the stopwatch (= 0), the mass is

(a) at the mean position,

(b) at the maximum stretched position, and

(c) at the maximum compressed position.

In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase?


Answer the following questions:

A time period of a particle in SHM depends on the force constant and mass of the particle: `T = 2pi sqrt(m/k)` A simple pendulum executes SHM approximately. Why then is the time 

 


The cylindrical piece of the cork of density of base area and height floats in a liquid of density `rho_1`. The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period

`T = 2pi sqrt((hrho)/(rho_1g)` 

where ρ is the density of cork. (Ignore damping due to viscosity of the liquid).


Show that, under certain conditions, simple pendulum performs the linear simple harmonic motion.


If the particle starts its motion from mean position, the phase difference between displacement and acceleration is ______.


A simple pendulum has a time period of T1 when on the earth's surface and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. The value of `"T"_2 // "T"_1` is ______. 


The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside mine will be ______.


The relation between acceleration and displacement of four particles are given below: Which one of the particles is executing simple harmonic motion?


Which of the following statements is/are true for a simple harmonic oscillator?

  1. Force acting is directly proportional to displacement from the mean position and opposite to it.
  2. Motion is periodic.
  3. Acceleration of the oscillator is constant.
  4. The velocity is periodic.

When will the motion of a simple pendulum be simple harmonic?


The length of a second’s pendulum on the surface of earth is 1 m. What will be the length of a second’s pendulum on the moon?


Find the time period of mass M when displaced from its equilibrium position and then released for the system shown in figure.


A cylindrical log of wood of height h and area of cross-section A floats in water. It is pressed and then released. Show that the log would execute S.H.M. with a time period. `T = 2πsqrt(m/(Apg))` where m is mass of the body and ρ is density of the liquid.


A particle at the end of a spring executes simple harmonic motion with a period t1, while the corresponding period for another spring is t2. If the period of oscillation with the two springs in series is T, then ______.


If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is `x/2` times its original time period. Then the value of x is ______.


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