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A Simple Pendulum of Length L and Having a Bob of Mass M is Suspended in a Car. the Car is Moving on a Circular Track of Radius R with a Uniform Speed V. If the Pendulum Makes Small Oscillations in a Radial Direction About Its Equilibrium Position, What Will Be Its Time Period? - Physics

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प्रश्न

A simple pendulum of length and having a bob of mass is suspended in a car. The car is moving on a circular track of radius with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium position, what will be its time period?

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उत्तर १

The bob of the simple pendulum will experience the acceleration due to gravity and the centripetal acceleration provided by the circular motion of the car.

Acceleration due to gravity = g

Centripetal acceleration  = `v^2/R`

Where,

v is the uniform speed of the car

R is the radius of the track

Effective acceleration (aeff) is given as:

`a_"eff" = sqrt(g^2 + (v^2/R)^2)`

Time period, `T =  2pi sqrt(1/a_"eff")`

Where, l is the length of the pendulum

:. Time period, `T = 2pi sqrt(1/(g^2 + v^4/R^2))`

 

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उत्तर २

In this case, the bob of the pendulum is under the action of two accelerations.

1) Acceleration due to gravity 'g' acting vertically downwards.

2) Centripetal acceleration `a_c = v^2/R` acting along the horizontal direction.

:. Effective acceleration, `g' = sqrt(g^2 + a_c^2)` or `g' =  sqrt(g^2 + v^4/R^2)`

Now time period, `T' = 2pi sqrt(1/g) = 2pi sqrt(1/(sqrt(g^2 + v^4/R62)))`

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