हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Two identical springs of spring constant K are attached to a block of mass m and to fixed supports as shown in figure.

Advertisements
Advertisements

प्रश्न

Two identical springs of spring constant K are attached to a block of mass m and to fixed supports as shown in figure. When the mass is displaced from equilibrium position by a distance x towards right, find the restoring force

टिप्पणी लिखिए
Advertisements

उत्तर

When the mass is displaced from the equilibrium position by a distance x towards the right, the right spring gets compressed by x developing a restoring force kx towards the left on the block. The left spring is stretched by an amount of x developing a restoring force kx left on the block.


F1 = – kx (for left spring)

And F2 = – kx (for right spring)

Restoring force, F = F1 + F2 = – 2kx

∴ F = 2kx towards left.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Oscillations - Exercises [पृष्ठ १०२]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 14 Oscillations
Exercises | Q 14.20 | पृष्ठ १०२

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

If the metal bob of a simple pendulum is replaced by a wooden bob of the same size, then its time period will.....................

  1. increase
  2. remain same
  3. decrease
  4. first increase and then decrease.

When the length of a simple pendulum is decreased by 20 cm, the period changes by 10%. Find the original length of the pendulum.


let us take the position of mass when the spring is unstretched as x = 0, and the direction from left to right as the positive direction of the x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t = 0), the mass is

(a) at the mean position,

(b) at the maximum stretched position, and

(c) at the maximum compressed position.

In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase?


The acceleration due to gravity on the surface of moon is 1.7 ms–2. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? (g on the surface of earth is 9.8 ms–2)


Answer the following questions:

A time period of a particle in SHM depends on the force constant k and mass m of the particle: `T = 2pi sqrt(m/k)` A simple pendulum executes SHM approximately. Why then is the time 

 


Answer the following questions:

A man with a wristwatch on his hand falls from the top of a tower. Does the watch give correct time during the free fall?


Answer the following questions:

What is the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity?


The cylindrical piece of the cork of density of base area A and height h floats in a liquid of density `rho_1`. The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period

`T = 2pi sqrt((hrho)/(rho_1g)` 

where ρ is the density of cork. (Ignore damping due to viscosity of the liquid).


Define practical simple pendulum


If the particle starts its motion from mean position, the phase difference between displacement and acceleration is ______.


A simple pendulum has a time period of T1 when on the earth's surface and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. The value of `"T"_2 // "T"_1` is ______. 


The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside mine will be ______.


A particle executing S.H.M. has a maximum speed of 30 cm/s and a maximum acceleration of 60 cm/s2. The period of oscillation is ______.


The length of a second’s pendulum on the surface of earth is 1 m. What will be the length of a second’s pendulum on the moon?


Find the time period of mass M when displaced from its equilibrium position and then released for the system shown in figure.


A cylindrical log of wood of height h and area of cross-section A floats in water. It is pressed and then released. Show that the log would execute S.H.M. with a time period. `T = 2πsqrt(m/(Apg))` where m is mass of the body and ρ is density of the liquid.


A simple pendulum of time period 1s and length l is hung from a fixed support at O, such that the bob is at a distance H vertically above A on the ground (Figure). The amplitude is θ0. The string snaps at θ = θ0/2. Find the time taken by the bob to hit the ground. Also find distance from A where bob hits the ground. Assume θo to be small so that sin θo = θo and cos θo = 1.


If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is `x/2` times its original time period. Then the value of x is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×