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Two identical springs of spring constant K are attached to a block of mass m and to fixed supports as shown in figure.

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प्रश्न

Two identical springs of spring constant K are attached to a block of mass m and to fixed supports as shown in figure. When the mass is displaced from equilibrium position by a distance x towards right, find the restoring force

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उत्तर

When the mass is displaced from the equilibrium position by a distance x towards the right, the right spring gets compressed by x developing a restoring force kx towards the left on the block. The left spring is stretched by an amount of x developing a restoring force kx left on the block.


F1 = – kx (for left spring)

And F2 = – kx (for right spring)

Restoring force, F = F1 + F2 = – 2kx

∴ F = 2kx towards left.

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अध्याय 14: Oscillations - Exercises [पृष्ठ १०२]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 14 Oscillations
Exercises | Q 14.20 | पृष्ठ १०२

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