Advertisements
Advertisements
प्रश्न
What is the 5th term form the end of the AP 2, 7, 12, …., 47?
Advertisements
उत्तर
The given AP is 2, 7, 12, ..., 47.
Let us re-write the given AP in reverse order i.e. 47, 42, .., 12, 7, 2.
Now, the 5th term from the end of the given AP is equal to the 5th term from beginning ofthe AP 47, 42,.... ,12, 7, 2.
Consider the AP 47, 42,..., 12, 7, 2.
Here, a = 47 and d = 42 – 47 = –5
5th term of this AP
= 47 + (5 – 1) × (–5)
= 47 – 20
= 27
Hence, the 5th term from the end of the given AP is 27.
APPEARS IN
संबंधित प्रश्न
If the sum of first 7 terms of an A.P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A.P.
Ramkali required Rs 2,500 after 12 weeks to send her daughter to school. She saved Rs 100 in the first week and increased her weekly saving by Rs 20 every week. Find whether she will be able to send her daughter to school after 12 weeks.
What value is generated in the above situation?
Find the sum given below:
`7 + 10 1/2 + 14 + ... + 84`
If the sum of first m terms of an A.P. is the same as the sum of its first n terms, show that the sum of its first (m + n) terms is zero
Find the sum of the following arithmetic progressions:
a + b, a − b, a − 3b, ... to 22 terms
Find the 8th term from the end of the AP 7, 10, 13, ……, 184.
The fourth term of an A.P. is 11. The sum of the fifth and seventh terms of the A.P. is 34. Find its common difference.
If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term?
Divide 207 in three parts, such that all parts are in A.P. and product of two smaller parts will be 4623.
Find the sum of the first 15 terms of each of the following sequences having nth term as xn = 6 − n .
If the 10th term of an A.P. is 21 and the sum of its first 10 terms is 120, find its nth term.
The sum of the first n terms of an A.P. is 4n2 + 2n. Find the nth term of this A.P.
The first and last terms of an A.P. are 1 and 11. If the sum of its terms is 36, then the number of terms will be
If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =
In an A.P. (with usual notations) : given d = 5, S9 = 75, find a and a9
In an A.P., the sum of its first n terms is 6n – n². Find is 25th term.
Find the next 4 terms of the sequence `1/6, 1/4, 1/3`. Also find Sn.
Find the sum of all odd numbers between 351 and 373.
An Arithmetic Progression (A.P.) has 3 as its first term. The sum of the first 8 terms is twice the sum of the first 5 terms. Find the common difference of the A.P.
The sum of all two digit numbers is ______.
