हिंदी

Find the sum of numbers between 1 to 140, divisible by 4.

Advertisements
Advertisements

प्रश्न

Find the sum of numbers between 1 to 140, divisible by 4.

योग
Advertisements

उत्तर

The numbers between 1 to 140 divisible by 4 are

4, 8, 12, ......, 140

The above sequence is an A.P.

∴ a = 4, d = 8 – 4 = 4

Let the number of terms in the A.P. be n.

Then, tn = 140

Since tn = a + (n – 1)d,

140 = 4 + (n – 1)(4)

∴ 140 – 4 =  (n – 1)(4)

∴ 136 = (n – 1)(4)

∴ `136/4` = n – 1

∴ 34 + 1 = n

∴ n = 35

Now, `S_n = n/2 [2a + (n - 1)d]`

∴ `S_35 = 35/2 [2 xx 4 + (35 - 1)4]`

= `35/2 [8 + (34)4]`

= `35/2 [8 + 136]`

= `35/2 xx 144`

= 35 × 72

S35 = 2520

∴ The sum of numbers between 1 to 140, which are divisible by 4 is 2520.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Arithmetic Progression - Q.4

संबंधित प्रश्न

Find the sum of the following arithmetic progressions: 50, 46, 42, ... to 10 terms


Find the sum of all odd natural numbers less than 50.


Show that `(a-b)^2 , (a^2 + b^2 ) and ( a^2+ b^2) ` are in AP.


The sum of the first n terms of an AP is (3n2+6n) . Find the nth term and the 15th term of this AP. 


The sum of the first n terms in an AP is `( (3"n"^2)/2 +(5"n")/2)`. Find the nth term and the 25th term.


Find four consecutive terms in an A.P. whose sum is 12 and sum of 3rd and 4th term is 14.

(Assume the four consecutive terms in A.P. are a – d, a, a + d, a +2d) 


Find the sum of n terms of the series \[\left( 4 - \frac{1}{n} \right) + \left( 4 - \frac{2}{n} \right) + \left( 4 - \frac{3}{n} \right) + . . . . . . . . . .\]


If `4/5` , a, 2 are three consecutive terms of an A.P., then find the value of a


Suppose three parts of 207 are (a − d), a , (a + d) such that , (a + d)  >a >  (a − d). 


 Q.10


Q.12


In an A.P. (with usual notations) : given d = 5, S9 = 75, find a and a


The sum of first 15 terms of an A.P. is 750 and its first term is 15. Find its 20th term.


If the third term of an A.P. is 1 and 6th term is – 11, find the sum of its first 32 terms.


Find the sum of first 1000 positive integers.

Activity :- Let 1 + 2 + 3 + ........ + 1000

Using formula for the sum of first n terms of an A.P.,

Sn = `square`

S1000 = `square/2 (1 + 1000)`

= 500 × 1001

= `square`

Therefore, Sum of the first 1000 positive integer is `square`


Find the sum:

`(a - b)/(a + b) + (3a - 2b)/(a + b) + (5a - 3b)/(a + b) +` ... to 11 terms


The ratio of the 11th term to the 18th term of an AP is 2 : 3. Find the ratio of the 5th term to the 21st term, and also the ratio of the sum of the first five terms to the sum of the first 21 terms.


The students of a school decided to beautify the school on the Annual Day by fixing colourful flags on the straight passage of the school. They have 27 flags to be fixed at intervals of every 2 m. The flags are stored at the position of the middle most flag. Ruchi was given the responsibility of placing the flags. Ruchi kept her books where the flags were stored. She could carry only one flag at a time. How much distance did she cover in completing this job and returning back to collect her books? What is the maximum distance she travelled carrying a flag?


Find the sum of all odd numbers between 351 and 373.


Rohan repays his total loan of ₹ 1,18,000 by paying every month starting with the first installment of ₹ 1,000. If he increases the installment by ₹ 100 every month, what amount will be paid by him in the 30th installment? What amount of loan has he paid after 30th installment?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×