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प्रश्न
Find the sum of first 10 terms of the A.P.
4 + 6 + 8 + .............
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उत्तर
Here,
First term, a = 4
Common difference, d = 6 – 4 = 2
n = 10
`S = n/2 [2a + (n - 1)d]`
= `10/2 [2(4) + 9(2)]`
= 5[8 + 18]
= 5 × 26
= 130
संबंधित प्रश्न
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`7 + 10 1/2 + 14 + ... + 84`
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Q.2
The first term of an AP of consecutive integers is p2 + 1. The sum of 2p + 1 terms of this AP is ______.
The sum of 40 terms of the A.P. 7 + 10 + 13 + 16 + .......... is ______.
When the first term a, the number of terms n and the common difference d are known, which formula gives the sum of the first n terms of an Arithmetic Progression?
