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Verify Rolle'S Theorem for the Following Function on the Indicated Interval F(X) = Sin 3x on [0, π] ? - Mathematics

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प्रश्न

Verify Rolle's theorem for the following function on the indicated interval f(x) = sin 3x on [0, π] ?

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उत्तर

The given function is \[f\left( x \right) = \sin3x\] .

Since \[\sin3x\] is everywhere continuous and differentiable, \[\sin3x\]  is continuous on \[\left[ 0, \pi \right]\] and differentiable on \[\left( 0, \pi \right)\] .

Also,

\[f\left( \pi \right) = f\left( 0 \right) = 0\]
Thus, \[f\left( x \right)\] satisfies all the conditions of Rolle's theorem.
Now, we have to show that there exists \[c \in \left( 0, \pi \right)\] such that 
\[f'\left( c \right) = 0\] .
We have
\[f\left( x \right) = \sin3x\]
\[ \Rightarrow f'\left( x \right) = 3\cos3x\]
\[\therefore f'\left( x \right) = 0\]
\[ \Rightarrow 3\cos3x = 0\]
\[ \Rightarrow \cos3x = 0\]
\[ \Rightarrow 3x = \frac{\pi}{2}, \frac{3\pi}{2}, . . . . \]
\[ \Rightarrow x = \frac{\pi}{6}, \frac{\pi}{2}, \frac{5\pi}{6}\]
Thus,\[c = \frac{\pi}{6}, \frac{\pi}{2}, \frac{5\pi}{6} \in \left( 0, \pi \right)\] such that \[f'\left( c \right) = 0\] .
​Hence, Rolle's theorem is verified.
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अध्याय 15: Mean Value Theorems - Exercise 15.1 [पृष्ठ ९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 15 Mean Value Theorems
Exercise 15.1 | Q 3.08 | पृष्ठ ९

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