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If F (X) = Ex Sin X in [0, π], Then C in Rolle'S Theorem is

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प्रश्न

If f (x) = ex sin x in [0, π], then c in Rolle's theorem is


विकल्प

  • π/6

  • π/4

  • π/2

  • 3π/4

MCQ
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उत्तर

3π/4
The given function is 

\[f\left( x \right) = e^x \sin x\].
Differentiating the given function with respect to x, we get 

\[f'\left( x \right) = e^x \cos n x + \sin x e^x \]

\[ \Rightarrow f'\left( c \right) = e^c \cos c + \sin c e^c \]

\[\text{Now }, e^x cos x \text { is continuous and derivable in R } . \]

\[\text { Therefore, it is continuous on } \left[ 0, \pi \right] \text { and derivable on} \left( 0, \pi \right) . \]

\[ \therefore f'\left( c \right) = 0 \]

\[ \Rightarrow e^c \left( \cos c + \sin c \right) = 0\]

\[ \Rightarrow \left( \cos c + \sin c \right) = 0 \left( \because e^c \neq 0 \right)\]

\[ \Rightarrow \tan c = - 1\]

\[ \Rightarrow c = \frac{3\pi}{4}, \frac{7\pi}{4}, . . . \]

\[ \therefore c = \frac{3\pi}{4} \in \left( 0, \pi \right)\]

Thus, \[c = \frac{3\pi}{4} \in \left( 0, \pi \right)\]for which Rolle's theorem holds.
Hence, the required value of c is 3π/4.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Mean Value Theorems - Exercise 15.4 [पृष्ठ २०]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 14 Mean Value Theorems
Exercise 15.4 | Q 11 | पृष्ठ २०

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