हिंदी

Use ruler and compasses for the following question taking a scale of 10 m = 1 cm. A park in a city is bounded by straight fences AB, BC, CD and DA. Given that AB = 50 m, BC = 63 m, ∠ABC = 75°

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प्रश्न

Use ruler and compasses for the following question taking a scale of 10 m = 1 cm. A park in a city is bounded by straight fences AB, BC, CD and DA. Given that AB = 50 m, BC = 63 m, ∠ABC = 75°. D is a point equidistant from the fences AB and BC. If ∠BAD = 90°, construct the outline of the park ABCD. Also locate a point P on the line BD for the flag post which is equidistant from the corners of the park A and B.

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उत्तर

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संबंधित प्रश्न

In parallelogram ABCD, side AB is greater than side BC and P is a point in AC such that PB bisects angle B. Prove that P is equidistant from AB and BC. 


Use ruler and compasses only for this question.

  1. Construct ΔABC, where AB = 3.5 cm, BC = 6 cm and ∠ABC = 60°.
  2. Construct the locus of points inside the triangle which are equidistant from BA and BC.
  3. Construct the locus of points inside the triangle which are equidistant from B and C.
  4. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.

Describe the locus of points at a distance 2 cm from a fixed line. 


Describe the locus of points inside a circle and equidistant from two fixed points on the circumference of the circle. 


Describe the locus of the centres of all circles passing through two fixed points. 


By actual drawing obtain the points equidistant from lines m and n; and 6 cm from a point P, where P is 2 cm above m, m is parallel to n and m is 6 cm above n. 


Prove that the common chord of two intersecting circles is bisected at right angles by the line of centres.


Find the locus of the centre of a circle of radius r touching externally a circle of radius R.


In Fig. AB = AC, BD and CE are the bisectors of ∠ABC and ∠ACB respectively such that BD and CE intersect each other at O. AO produced meets BC at F. Prove that AF is the right bisector of BC.


Given: ∠BAC, a line intersects the arms of ∠BAC in P and Q. How will you locate a point on line segment PQ, which is equidistant from AB and AC? Does such a point always exist?


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