Advertisements
Advertisements
प्रश्न
Two resistors of resistance 4 Ω and 6 Ω are connected in parallel to a cell to draw 0.5 A current from the cell.
Calculate current in each resistor.
Advertisements
उत्तर
Equivalent resistance of the circuit:
`1/"R" = 1/4 + 1/6 = (3+2)/12 = 5/12`
`therefore "R" = 12/5 = 2.4 Omega`
Hence, the emf of the cell is
V = IR
∴ V = 0.5 × 2.4
∴ V = 1.2 V
Therefore, current through each resistor is
`"I"_4 = "V"/"R"_4 = 1.2/4 = 0.3 "A"`
`"I"_6 = "V"/"R"_6 = 1.2/6 = 0.2 "A"`
संबंधित प्रश्न
Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of 9 Ω.
A wire of resistance R1 is cut into five equal pieces. These five pieces of wire are then connected in parallel. If the resultant resistance of this combination be R2, then the ratio `R_1/R_2` is:
(a) `1/25`
(b)1/5
(c)5
(c)25
Two resistances when connected in parallel give resultant value of 2 ohm; when connected in series the value becomes 9 ohm. Calculate the value of each resistance.
How will you connect three resistors of 2 Ω, 3 Ω and 5 Ω respectively so as to obtain a resultant of 2.5 Ω? Draw the diagram to show the arrangement.
State how are the two resistors joined with a battery when equivalent resistance is less than either of the two resistances.
You have three resistors of values 2Ω, 3Ω and 5Ω. How will you join them so that the total resistance is less than 1Ω? Draw diagram and find the total resistance.
A combination consists of three resistors in series. Four similar sets are connected in parallel. If the resistance of each resistor is 2 ohm, find the resistance of the combination.
What are the advantages of a parallel connection?
A current of 2 A is passed through a coil of resistance 75 Ω for 2 minutes.
(a) How much heat energy is produced?
(b) How much charge is passed through the resistance?
A given wire is stretched to double its length. How will its resistance change?
