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प्रश्न
Two resistors of resistance 4 Ω and 6 Ω are connected in parallel to a cell to draw 0.5 A current from the cell.
Calculate current in each resistor.
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उत्तर
Equivalent resistance of the circuit:
`1/"R" = 1/4 + 1/6 = (3+2)/12 = 5/12`
`therefore "R" = 12/5 = 2.4 Omega`
Hence, the emf of the cell is
V = IR
∴ V = 0.5 × 2.4
∴ V = 1.2 V
Therefore, current through each resistor is
`"I"_4 = "V"/"R"_4 = 1.2/4 = 0.3 "A"`
`"I"_6 = "V"/"R"_6 = 1.2/6 = 0.2 "A"`
संबंधित प्रश्न
Complete the following :-
(c)
What are the advantages of connecting electrical devices in parallel with the battery instead of connecting them in series?
Show how you would connect two 4 ohm resistors to produce a combined resistance of (a) 2 ohms (b) 8 ohms.
Explain with diagram what is meant by the "series combination" and "parallel combination" of resistances. In which case the resultant resistance is : (i) less, and (ii) more, than either of the individual resistances?
In the circuit given below:
(a) What is the combined resistance?
(b) What is the p.d. across the combined resistor?
(c) What is the p.d. across the 3 Ω resistor?
(d) What is the current in the 3 Ω resistor?
(e) What is the current in the 6 Ω resistor?
In parallel combination of resistances ______.
Two resistors of resistance 4 Ω and 6 Ω are connected in parallel to a cell to draw 0.5 A current from the cell.
Draw a labeled diagram of the arrangement
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Reason: In a short circuit, the current is zero.
Two resistors having resistance 8 Ω and 12 Ω are connected in parallel. Find their equivalent resistance.
