Advertisements
Advertisements
प्रश्न
Two resistors of resistance 4 Ω and 6 Ω are connected in parallel to a cell to draw 0.5 A current from the cell.
Calculate current in each resistor.
Advertisements
उत्तर
Equivalent resistance of the circuit:
`1/"R" = 1/4 + 1/6 = (3+2)/12 = 5/12`
`therefore "R" = 12/5 = 2.4 Omega`
Hence, the emf of the cell is
V = IR
∴ V = 0.5 × 2.4
∴ V = 1.2 V
Therefore, current through each resistor is
`"I"_4 = "V"/"R"_4 = 1.2/4 = 0.3 "A"`
`"I"_6 = "V"/"R"_6 = 1.2/6 = 0.2 "A"`
संबंधित प्रश्न
With a neat labelled diagram and derive the equation for three resistances connected in parallel.
Explain with the help of a labelled circuit diagram, how you will find the resistance of a combination of three resistors of resistances R1, R2 and R3 joined in parallel.
Two resistances when connected in parallel give resultant value of 2 ohm; when connected in series the value becomes 9 ohm. Calculate the value of each resistance.
How will you connect three resistors of 2 Ω, 3 Ω and 5 Ω respectively so as to obtain a resultant of 2.5 Ω? Draw the diagram to show the arrangement.
How will you connect three resistors of resistances 2 Ω, 3 Ω, and 6 Ω to obtain a total resistance of 4 Ω, and 1 Ω?
A combination consists of three resistors in series. Four similar sets are connected in parallel. If the resistance of each resistor is 2 ohm, find the resistance of the combination.
In the following figure calculate:
- the total resistance of the circuit
- the value of R, and
- the current flowing in R.
Solve the following question:
In an electric circuit, two resistors of 12 0 each are joined in parallel to a 6 V battery. Find the current drawn from the battery.
Two resistors when connected in parallel give the resultant resistance of 2 ohms, but when connected in series the effective resistance becomes 9 ohms. Calculate the value of each resistance.
Three resistors of 6Ω, 4Ω and 4Ω are connected together so that the total resistance is 8Ω. Draw a diagram to show this arrangement and give reason to justify your answer.
