Question

Two cells each of 5V are connected in series across an 8Ω resistor and three parallel resistors of 4Ω, 6Ω, and 12Ω. Draw a circuit diagram for the above arrangement. Calculate

1. the current drawn from the cell
2. current through each resistor

Answer 1

i) Current drawn from the cell

E_eq = 5+5 = 10V

R_eff = R_s+ R_p

R_s = 8 Ω

`1/"R"_"p" = 1/4 + 1/6 + 1/12`

`= (18 + 12 + 6)/72 = 36/72`

∴ R_p = `72/36` = 2 Ω

R_eff = 8 + 2 = 10Ω

I = `"E"_"eq"/"R"_"eff" = 10/10 = 1`A

∴ I = 1A

Voltage drop V= IR =1 × 2 = 2V

V = 2V

ii) Current through each resistor:

∴ current in 4Ω resistor

I = 24 = O.5A

I = O.5A

current in 6Ω resistor, I = `2/6` = 0.33 A

I = 0.33A

current in 12Ω resistor, I = `2/12 = 1/6` = 0.17A

I = 0.17A