Advertisements
Advertisements
प्रश्न
Trapezium given below; find its area.
Advertisements
उत्तर
For the triangle EBC,
S = 19 cm
Area of ΔEBC = `sqrt( 19 xx ( 19 - 16 ) xx ( 19 - 12 ) xx ( 19 - 10 ))`
= `sqrt( 19 xx 3 xx 7 xx 9 )`
= 59.9 sq.cm
Let h be the height.
Area of ΔEBC= `1/2` x 12 x h
⇒ 59.9 = 6h
⇒ h = `59.9/6` = 9.98 cm
Area of ABCD = `1/2` x ( 20 + 32 ) x 9.98
= `1/2` x 52 x 9.98
= 259.48 cm2
APPEARS IN
संबंधित प्रश्न
Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.
The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.
Find the area of a quadrilateral one of whose diagonals is 30 cm long and the perpendiculars from the other two vertices are 19 cm and 11 cm respectively.
Trapezium given below; find its area.
Calculate the area of the figure given below:
Which is not drawn scale.
The width of a rectangular room is `4/7`of its length, x, and its perimeter is y. Write an equation connecting x and y. Find the length of the room when the perimeter is 4400 cm.
The length of a rectangular verandah is 3 m more than its breadth. The numerical value of its area is equal to the numerical value of its perimeter.
(i) Taking x as the breadth of the verandah, write an equation in x that represents the above statement
(ii) Solve the equation obtained in (i) above and hence find the dimensions of the verandah.
Sum of the areas of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of the two squares.
When proving that a quadrilateral is a trapezium, it is necessary to show
When proving that a quadrilateral is a parallelogram by using slopes you must find
