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Total number of orbitals associated with third shell will be ______.

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प्रश्न

Total number of orbitals associated with third shell will be ______.

विकल्प

  • 2

  • 4

  • 9

  • 3

MCQ
रिक्त स्थान भरें
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उत्तर

Total number of orbitals associated with third shell will be 9.

Explanation:

The total number of orbitals is given by n2, where n is the principal quantum number or the principal shell.

Thus for the third shell number of orbitals is 32 i.e. 9.

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अध्याय 2: Structure of Atom - Multiple Choice Questions (Type - I) [पृष्ठ १६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 2 Structure of Atom
Multiple Choice Questions (Type - I) | Q 11 | पृष्ठ १६

संबंधित प्रश्न

Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l =3.


Choose the correct option.

Principal Quantum number describes -


State the order of filling atomic orbitals following Aufbau principle.


Write orbital notations for the electron in orbitals with the following quantum numbers.

n = 2, l = 1


Write condensed orbital notation of electronic configuration of the following element:

Silicon (Z = 14)


Write condensed orbital notation of electronic configuration of the following element:

Chlorine (Z = 17)


Explain in brief, the significance of the azimuthal quantum number.


If n = 3, what are the quantum number l and m?


Which one of the following orders is CORRECT in case of energy of the given subshells?

P: n = 4; l = 3

Q: n = 5; I = 1

R: n = 5; l = 0

S: n = 4; l = 2


Which of the following properties of atom could be explained correctly by Thomson Model of atom?


The number of radial nodes for 3p orbital is ______.


Orbital angular momentum depends on ______.


The pair of ions having same electronic configuration is ______.


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

In which of the following pairs, the ions are iso-electronic?

(i) \[\ce{Na^{+}, Mg^{2+}}\]

(ii) \[\ce{Al3^{+}, O-}\]

(iii) \[\ce{Na+ , O2-}\]

(iv) \[\ce{N3-, Cl-}\]


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


Match the quantum numbers with the information provided by these.

Quantum number Information provided
(i) Principal quantum number (a) orientation of the orbital
(ii) Azimuthal quantum number (b) energy and size of orbital
(iii) Magnetic quantum number (c) spin of electron
(iv) Spin quantum number (d) shape of the orbital

Match species given in Column I with the electronic configuration given in Column II.

Column I Column II
(i) \[\ce{Cr}\] (a) [Ar]3d84s0
(ii) \[\ce{Fe^{2+}}\] (b) [Ar]3d104s1
(iii) \[\ce{Ni^{2+}}\] (c) [Ar]3d64s0
(iv) \[\ce{Cu}\] (d) [Ar] 3d54s1
  (e) [Ar]3d64s2

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