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The Value of Tan { Cos − 1 1 5 √ 2 − Sin − 1 4 √ 17 } is (A) √ 29 3 (B) 29 3 (C) √ 3 29 (D) 3 29 - Mathematics

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प्रश्न

The value of tan \[\left\{ \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right\}\] is

 

विकल्प

  • `sqrt29/3`

  • `29/3`

  • `sqrt3/29`

  • `3/29`

MCQ
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उत्तर

(d) `3/29`

\[\text{ Let }, \cos^{- 1} \frac{1}{5\sqrt{2}} = y \text{ and } \sin^{- 1} \frac{4}{\sqrt{17}} = z\]
\[\therefore \cos{y} = \frac{1}{5\sqrt{2}} \Rightarrow \sin{y} = \frac{7}{5\sqrt{2}} \Rightarrow \tan{y} = 7\]
\[\sin{z} = \frac{4}{\sqrt{17}} \Rightarrow \cos{z} = \frac{1}{\sqrt{17}} \Rightarrow \tan{z} = 4\]
\[\therefore \tan\left( \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right) = \tan\left( y - z \right)\]
\[ = \frac{\tan{y} - \tan{z}}{1 + \tan{y} \tan{z}}\]
\[ = \frac{7 - 4}{1 + 7 \times 4}\]
\[ = \frac{3}{29}\]
\[\therefore \tan\left( \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right) = \tan\left( y - z \right)\]
\[ = \frac{\tan{y} - \tan{z}}1 + \tan{y} \tan{z}\]
\[ = \frac{7 - 4}{1 + 7 \times 4}\]
\[ = \frac{3}{29}\]

 

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.16 [पृष्ठ १२०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 2 | पृष्ठ १२०

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