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Solve the Following: `Sin^-1x+Sin^-1 2x=Pi/3` - Mathematics

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प्रश्न

Solve the following:

`sin^-1x+sin^-1  2x=pi/3`

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उत्तर

We know

`sin^-1x+sin^-1y=sin^-1[xsqrt(1-y^2)+ysqrt(1-x^2)]`

∴ `sin^-1x+sin^-1  2x=pi/3`

⇒ `sin^-1x+sin^-1  2x=sin^-1(sqrt3/2)`

⇒ `sin^-1x-sin^-1(sqrt3/2)=-sin^-1  2x`

⇒ `sin^-1[xsqrt(1-3/4)+sqrt3/2sqrt(1-x^2)]=-sin^-1  2x`

⇒ `sin^-1[x/2+sqrt3/2sqrt(1-x^2)]=sin^-1(-2x)`

⇒ `x/2+sqrt3/2sqrt(1-x^2)=-2x`

⇒ `x+sqrt3sqrt(1-x^2)=-4x`

⇒ `5x=-sqrt3sqrt(1-x^2)`

Squaring both the sides,

`25x^2=3-3x^2`

⇒ `28x^2=3`

⇒ `x=+-1/2sqrt(3/7)`

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.12 [पृष्ठ ८९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.12 | Q 3.1 | पृष्ठ ८९

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