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`2tan^-1 1/5+Tan^-1 1/8=Tan^-1 4/7` - Mathematics

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प्रश्न

`2tan^-1  1/5+tan^-1  1/8=tan^-1  4/7`

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उत्तर

LHS = `2tan^-1  1/5+tan^-1  1/8`

`=tan^-1{(2xx1/5)/(1-(1/5)^2)}+tan^-1  1/8`     `[because2tan^-1x=tan^-1{(2x)/(1-x^2)}]`

`=tan^-1{(2/5)/(24/25)}+tan^-1  1/8`

`=tan^-1  5/12+tan^-1  1/8`

`=tan^-1((5/12+1/8)/(1-5/12xx1/8))`       `[becausetan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))]`

`=tan^-1((13/24)/(91/96))`

`=tan^-1  4/7`= RHS

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.14 [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.14 | Q 2.07 | पृष्ठ ११५

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