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Solve the Following Equation For X: `Tan^-1 (X-2)/(X-1)+Tan^-1 (X+2)/(X+1)=Pi/4` - Mathematics

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प्रश्न

Solve the following equation for x:

`tan^-1  (x-2)/(x-1)+tan^-1  (x+2)/(x+1)=pi/4`

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उत्तर

`tan^-1  (x-2)/(x-1)+tan^-1  (x+2)/(x+1)=pi/4`

⇒ `tan^-1(((x-2)/(x-1)+(x+2)/(x+1))/(1-((x-2)/(x-1))((x+2)/(x+1))))=pi/4`       `[tan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))]`

⇒ `((((x-2)(x+1)+(x-1)(x+2))/((x-1)(x+1))))/((((x-1)(x+1)-(x-2)(x+2))/((x-1)(x+1))))=tan (pi/4)`

⇒ `((x-2)(x+1)+(x-1)(x+2))/((x-1)(x+1)-(x-2)(x+2))=1`

⇒ `(x^2-x-2+x^2+x-2)/((x^2-1)-(x^2-4))=1`

⇒ `(2x^2-4)/3=1`

⇒ `2x^2-4=3`

⇒ `2x^2=7`

⇒ `x^2=7/2`

∴ `x=+-sqrt(7/2`

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.11 [पृष्ठ ८२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.11 | Q 3.1 | पृष्ठ ८२

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