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Write the Principal Value of Sin − 1 ( − 1 2 ) - Mathematics

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प्रश्न

Write the principal value of `sin^-1(-1/2)`

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उत्तर

Let `y=sin^-1(-1/2)`

Then,

\[\sin{y} = - \frac{1}{2} = \sin\left( - \frac{\pi}{6} \right)\]
\[y = - \frac{\pi}{6} \in \left[ - \frac{\pi}{2}, \frac{\pi}{2} \right]\]
Here, 
\[\left[ - \frac{\pi}{2}, \frac{\pi}{2} \right]\]  is the range of the principal value branch of the inverse sine function.
∴ \[\sin^{- 1} \left( - \frac{1}{2} \right) = - \frac{\pi}{6}\]

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११८]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 39 | पृष्ठ ११८

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