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Evaluate Sin - Mathematics

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प्रश्न

Evaluate sin \[\left( \tan^{- 1} \frac{3}{4} \right)\]

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उत्तर

We know that

\[\tan^{- 1} x = \sin^{- 1} \frac{x}{\sqrt{1 + x^2}}\]

\[\therefore \sin\left( \tan^{- 1} \frac{3}{4} \right) = \sin\left\{ \sin^{- 1} \left( \frac{\frac{3}{4}}{\sqrt{1 + \frac{9}{16}}} \right) \right\}\]
\[ = \sin\left\{ \sin^{- 1} \left( \frac{\frac{3}{4}}{\frac{5}{4}} \right) \right\}\]
\[ = \sin\left( \sin^{- 1} \frac{3}{5} \right)\]
\[ = \frac{3}{5} \left[ \because \sin\left( \sin^{- 1} x \right) = x \right]\]

∴ \[\sin\left( \tan^{- 1} \frac{3}{4} \right) = \frac{3}{5}\]

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 18 | पृष्ठ ११७

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