हिंदी

Evaluate the Following: `Sec^-1(Sec (5pi)/4)` - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`sec^-1(sec  (5pi)/4)`

Advertisements

उत्तर

We know that

sec-1 (sec θ) = θ,    [0, π/2) ∪ (π/2, π]

 We have 

`sec^-1(sec  (5pi)/4)=sec^-1[sec(2pi-(3pi)/4)]`

`=sec^-1[sec((3pi)/4)]`

`=(3pi)/4`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Inverse Trigonometric Functions - Exercise 4.07 [पृष्ठ ४२]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.07 | Q 4.3 | पृष्ठ ४२

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Write the value of `tan(2tan^(-1)(1/5))`


If a line makes angles 90° and 60° respectively with the positive directions of x and y axes, find the angle which it makes with the positive direction of z-axis.


Find the domain of definition of `f(x)=cos^-1(x^2-4)`


Find the domain of  `f(x) =2cos^-1 2x+sin^-1x.`


​Find the principal values of the following:

`cos^-1(sin   (4pi)/3)`


`sin^-1(sin  pi/6)`


`sin^-1(sin  (5pi)/6)`


Evaluate the following:

`cos^-1{cos  ((4pi)/3)}`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`tan^-1(tan1)`


Evaluate the following:

`tan^-1(tan4)`


Evaluate the following:

`sec^-1(sec  (7pi)/3)`


Evaluate the following:

`cot(cos^-1  3/5)`


Evaluate:

`cos{sin^-1(-7/25)}`


Evaluate:

`sec{cot^-1(-5/12)}`


Evaluate:

`tan{cos^-1(-7/25)}`


Evaluate:

`cot(tan^-1a+cot^-1a)`


`sin^-1x=pi/6+cos^-1x`


Prove the following result:

`tan^-1  1/7+tan^-1  1/13=tan^-1  2/9`


Solve the following equation for x:

`tan^-1  (x-2)/(x-1)+tan^-1  (x+2)/(x+1)=pi/4`


Solve the following:

`cos^-1x+sin^-1  x/2=π/6`


If `cos^-1  x/2+cos^-1  y/3=alpha,` then prove that  `9x^2-12xy cosa+4y^2=36sin^2a.`


`2tan^-1  3/4-tan^-1  17/31=pi/4`


Solve the following equation for x:

`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`


Prove that:

`tan^-1  (2ab)/(a^2-b^2)+tan^-1  (2xy)/(x^2-y^2)=tan^-1  (2alphabeta)/(alpha^2-beta^2),`   where `alpha=ax-by  and  beta=ay+bx.`


If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2,`  then write the value of x + y + z.


Write the value of cos \[\left( 2 \sin^{- 1} \frac{1}{2} \right)\]


Write the value of tan1\[\left\{ \tan\left( \frac{15\pi}{4} \right) \right\}\]


Write the value of cos−1 \[\left( \cos\frac{5\pi}{4} \right)\]


If \[\tan^{- 1} (\sqrt{3}) + \cot^{- 1} x = \frac{\pi}{2},\] find x.


Write the principal value of \[\cos^{- 1} \left( \cos\frac{2\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{2\pi}{3} \right)\]


Write the value of \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]


Write the value of  `cot^-1(-x)`  for all `x in R` in terms of `cot^-1(x)`


Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]


The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is 

 


The domain of  \[\cos^{- 1} \left( x^2 - 4 \right)\] is

 


Prove that : \[\tan^{- 1} \left( \frac{\sqrt{1 + x^2} + \sqrt{1 - x^2}}{\sqrt{1 + x^2} - \sqrt{1 - x^2}} \right) = \frac{\pi}{4} + \frac{1}{2} \cos^{- 1} x^2 ;  1 < x < 1\].


Find the domain of `sec^(-1)(3x-1)`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×