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Solve the Following Equation For X: `2tan^-1(Sinx)=Tan^-1(2sinx),X!=Pi/2` - Mathematics

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प्रश्न

Solve the following equation for x:

`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`

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उत्तर

`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`

`=>tan^-1((2sinx)/(1-sin^2x))=tan^-1(2sinx)`     `[because2tan^-1x=tan^-1((2x)/(1-x^2))]`

`=>(2sinx)/(1-sin^2x)=2sinx`

`=>2sinx=2sinx-2sin^3x`

`=>2sin^2x=0`

`=>sinx=0`

`=>x=0`

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.14 [पृष्ठ ११६]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.14 | Q 8.4 | पृष्ठ ११६

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