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Evaluate: `Sin(Tan^-1x+Tan^-1 1/X)` for X < 0 - Mathematics

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प्रश्न

Evaluate:

`sin(tan^-1x+tan^-1  1/x)` for x < 0

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उत्तर

`sin(tan^-1x+tan^-1  1/x)=sin[tan^-1(-x)+tan^-1(-1/x)]`    `[thereforex<0]`

`=sin[-tan^-1(x)-tan^-1(1/x)]`

`=sin{-[tan^-1(x)+tan^-1(1/x)]}`

`=sin[-(tan^-1x+cot^-1x)]`       `[thereforetan^-1  1/x=cot^-1x]`

`=-sin(tan^-1x+cot^-1x)`

`=-sin(pi/2)`    `[thereforetan^-1x+cot^-1x=pi/2]`

= -1

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.10 [पृष्ठ ६६]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.10 | Q 1.2 | पृष्ठ ६६

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