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प्रश्न
`tan^-1x+2cot^-1x=(2x)/3`
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उत्तर
`tan^-1x+2cot^-1x=(2x)/3`
⇒ `tan^-1x+2(pi/2-tan^-1x)=(2pi)/3` `[becausecot^-1x=pi/2-tan^-1x]`
⇒ `tan^-1x+pi-2tan^-1x=(2pi)/3`
⇒ `tan^-1x=pi/3`
⇒ `x=tan pi/3=sqrt3`
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