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Write the Value of Sin−1 \[\Left( \Sin( -{600}\Circ) \Right)\]. - Mathematics

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प्रश्न

Write the value of sin−1

\[\left( \sin( -{600}°) \right)\].

 

 

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उत्तर

We know that

\[\sin^{- 1} \left(\sin{x} \right) = x\]

Now,

\[\sin^{- 1} \left\{ \sin\left( - {600}^\circ \right) \right\} = \sin^{- 1} \left\{ \sin\left( {720}^\circ - {600}^\circ \right) \right\}\]
\[ = \sin^{- 1} \left\{ \sin\left( {120}^\circ \right) \right\}\]
\[ = \sin^{- 1} \left\{ \sin\left( {180}^\circ - {120}^\circ \right) \right\} \left[ \because \sin{x} = \sin\left( \pi - x \right) \right]\]
\[ = \sin^{- 1} \left( \sin {60}^\circ \right)\]
\[ = {60}^\circ\]

∴ \[\sin^{- 1} \left\{ \sin\left( - {600}^\circ \right) \right\} = {60}^\circ\]

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 14 | पृष्ठ ११७

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