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If α = Tan − 1 ( Tan 5 π 4 ) and β = Tan − 1 ( − Tan 2 π 3 ) , Then (A) 4 α = 3 β (B) 3 α = 4 β (C) α − β = 7 π 12 (D) None of These - Mathematics

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प्रश्न

If α = \[\tan^{- 1} \left( \tan\frac{5\pi}{4} \right) \text{ and }\beta = \tan^{- 1} \left( - \tan\frac{2\pi}{3} \right)\] , then

 

विकल्प

  • 4 α = 3 β

  • 3 α = 4 β

  • α − β = `(7pi)/12`

  • none of these

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उत्तर

(a) 4 α = 3 β
We know that 

\[\tan^{- 1} \left( \tan{x} \right) = x\]
\[\therefore \alpha = \tan^{- 1} \left( \tan\frac{5\pi}{4} \right)\]
\[ = \tan^{- 1} \left\{ \tan\left( \pi + \frac{\pi}{4} \right) \right\}\]
\[ = \tan^{- 1} \left( \tan\frac{\pi}{4} \right)\]
\[ = \frac{\pi}{4}\]
and
\[\beta = \tan^{- 1} \left\{ - \tan\left( \frac{2\pi}{3} \right) \right\}\]
\[ = \tan^{- 1} \left\{ - \tan\left( \pi - \frac{\pi}{3} \right) \right\}\]
\[ = \tan^{- 1} \left\{ \tan\left( \frac{\pi}{3} \right) \right\}\]
\[ = \frac{\pi}{3}\]
\[\therefore 4\alpha = \pi\]
\[3\beta = \pi\]
∴ \[4\alpha = 3\beta\]

 

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.16 [पृष्ठ १२०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 9 | पृष्ठ १२०

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