Advertisements
Advertisements
प्रश्न
Evaluate the following:
`cot(cos^-1 3/5)`
Advertisements
उत्तर
`cot(cos^-1 3/5)=cot{tan^-1 sqrt(1-(3/5)^2)/(3/5)}` `[thereforecos^-1x=tan^-1 (sqrt(1-z^2)/x)]`
`=cot(tan^-1 (4/5)/(8/17))`
`=cot(cot^-1 3/4)`
`=3/4`
APPEARS IN
संबंधित प्रश्न
Find the domain of definition of `f(x)=cos^-1(x^2-4)`
Find the principal values of the following:
`cos^-1(tan (3pi)/4)`
`sin^-1(sin3)`
`sin^-1(sin4)`
`sin^-1(sin2)`
Evaluate the following:
`cos^-1{cos(-pi/4)}`
Evaluate the following:
`cos^-1{cos (5pi)/4}`
Evaluate the following:
`tan^-1(tan4)`
Evaluate the following:
`sec^-1(sec pi/3)`
Evaluate the following:
`cosec^-1(cosec (11pi)/6)`
Evaluate the following:
`cot^-1(cot (19pi)/6)`
Write the following in the simplest form:
`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`
Write the following in the simplest form:
`tan^-1{(sqrt(1+x^2)+1)/x},x !=0`
Evaluate the following:
`sin(tan^-1 24/7)`
Evaluate the following:
`sec(sin^-1 12/13)`
Evaluate the following:
`cos(tan^-1 24/7)`
Evaluate:
`cot{sec^-1(-13/5)}`
If `(sin^-1x)^2+(cos^-1x)^2=(17pi^2)/36,` Find x
Solve the following equation for x:
cot−1x − cot−1(x + 2) =`pi/12`, x > 0
`2tan^-1(1/2)+tan^-1(1/7)=tan^-1(31/17)`
Find the value of the following:
`tan^-1{2cos(2sin^-1 1/2)}`
Prove that:
`tan^-1 (2ab)/(a^2-b^2)+tan^-1 (2xy)/(x^2-y^2)=tan^-1 (2alphabeta)/(alpha^2-beta^2),` where `alpha=ax-by and beta=ay+bx.`
Write the value of tan−1x + tan−1 `(1/x)`for x > 0.
What is the value of cos−1 `(cos (2x)/3)+sin^-1(sin (2x)/3)?`
Write the value of
\[\cos^{- 1} \left( \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\].
Write the value of cos2 \[\left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right)\]
Write the value of sin−1 \[\left( \cos\frac{\pi}{9} \right)\]
If \[\sin^{- 1} \left( \frac{1}{3} \right) + \cos^{- 1} x = \frac{\pi}{2},\] then find x.
Write the value of \[\tan\left( 2 \tan^{- 1} \frac{1}{5} \right)\]
Write the principal value of `tan^-1sqrt3+cot^-1sqrt3`
Write the value of \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]
Write the value of \[\sec^{- 1} \left( \frac{1}{2} \right)\]
Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]
2 tan−1 {cosec (tan−1 x) − tan (cot−1 x)} is equal to
If x < 0, y < 0 such that xy = 1, then tan−1 x + tan−1 y equals
If \[\cos^{- 1} \frac{x}{2} + \cos^{- 1} \frac{y}{3} = \theta,\] then 9x2 − 12xy cos θ + 4y2 is equal to
The value of \[\cos^{- 1} \left( \cos\frac{5\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{5\pi}{3} \right)\] is
Write the value of \[\cos^{- 1} \left( - \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\] .
Find the value of x, if tan `[sec^(-1) (1/x) ] = sin ( tan^(-1) 2) , x > 0 `.
The equation sin-1 x – cos-1 x = cos-1 `(sqrt3/2)` has ____________.
