Question

`sin^-1(sin  (7pi)/6)`

Answer 1

We know

`sin(sin^-1theta)=theta if - pi/2<=theta<=pi/2`

We have

`sin^-1(sin  (7pi)/6)=sin^-1{sin(pi+pi/6)}`

`=sin^-1(sin-pi/6)`

`=-pi/6`