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प्रश्न
Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]
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उत्तर
\[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right) = \tan^{- 1} \left[ \tan\left( \pi + \frac{\pi}{8} \right) \right]\]
\[ = \tan^{- 1} \left[ \tan\left( \frac{\pi}{8} \right) \right]\]
\[ = \frac{\pi}{8}\]
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