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Prove the Following Result: `Tan^-1 1/4+Tan^-1 2/9=Sin^-1 1/Sqrt5` - Mathematics

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प्रश्न

Prove the following result:

`tan^-1  1/4+tan^-1  2/9=sin^-1  1/sqrt5`

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उत्तर

LHS = `tan^-1  1/4+tan^-1  2/9`

`=tan^-1((1/4+2/9)/(1-1/4xx2/9))`     `[becausetan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))]`

`=tan^-1((17/36)/(34/36))`

`=tan^-1  1/2`

`=sin^-1  (1/2)/sqrt(1+(1/2)^2)`

`=sin^-1  1/5=`RHS

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.11 [पृष्ठ ८२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.11 | Q 1.3 | पृष्ठ ८२

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