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प्रश्न
The sum of first six odd natural numbers is ______.
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उत्तर
The sum of first six odd natural numbers is 36.
Explanation:
∵ Every square can be expressed as a sum of successive odd natural numbers from 1.
⇒ The sum of first n odd natural numbers is n2
Here, n = 6
⇒ 1 + 3 + 5 + 7 + 9 + 11
= 6 × 6
= 36
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संबंधित प्रश्न
The squares of which of the following would be odd numbers?
- 431
- 2826
- 7779
- 82004
Observe the following pattern and supply the missing number.
112 = 121
1012 = 10201
101012 = 102030201
10101012 = _____
____2 = 10203040504030201.
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
Express 49 as the sum of 7 odd numbers.
How many numbers lie between squares of the given numbers?
25 and 26
How many numbers lie between squares of the following numbers?
99 and 100
64 is the square number of __________
Is 24 a square number?
Fill in the blank box.
