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प्रश्न
The sum of first six odd natural numbers is ______.
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उत्तर
The sum of first six odd natural numbers is 36.
Explanation:
∵ Every square can be expressed as a sum of successive odd natural numbers from 1.
⇒ The sum of first n odd natural numbers is n2
Here, n = 6
⇒ 1 + 3 + 5 + 7 + 9 + 11
= 6 × 6
= 36
APPEARS IN
संबंधित प्रश्न
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 1 ______ 2 ______ 1
100000012 = ______
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
|
Express 121 as the sum of 11 odd numbers.
How many numbers lie between squares of the given numbers?
12 and 13
How many numbers lie between squares of the following numbers?
99 and 100
64 is the square number of __________
Is 24 a square number?
1, 3, 6, _______, 15, _______, 28
The next two numbers in the number pattern 1, 4, 9, 16, 25 ... are ______.
The sum of first n odd natural numbers is n2.
