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प्रश्न
Express 81 as the sum of first nine consecutive odd numbers.
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उत्तर
The first nine consecutive odd numbers are 1, 3, 5, 7, 9, 11, 13, 15 and 17.
We have: 81
As, 81 is a perfect square.
So, 81 = (9)2
= 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17
= Sum of first nine consecutive odd numbers.
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संबंधित प्रश्न
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 1 ______ 2 ______ 1
100000012 = ______
Observe the following pattern and supply the missing number.
112 = 121
1012 = 10201
101012 = 102030201
10101012 = _____
____2 = 10203040504030201.
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
64 is the square number of __________
A number multiplied by _________ is called square of that number
Fill in the blank box.
The sum of first six odd natural numbers is ______.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
