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प्रश्न
The sum of first six odd natural numbers is ______.
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उत्तर
The sum of first six odd natural numbers is 36.
Explanation:
∵ Every square can be expressed as a sum of successive odd natural numbers from 1.
⇒ The sum of first n odd natural numbers is n2
Here, n = 6
⇒ 1 + 3 + 5 + 7 + 9 + 11
= 6 × 6
= 36
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संबंधित प्रश्न
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 1 ______ 2 ______ 1
100000012 = ______
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
Express 49 as the sum of 7 odd numbers.
How many numbers lie between squares of the given numbers?
12 and 13
How many numbers lie between squares of the given numbers?
25 and 26
Is 24 a square number?
The next two numbers in the number pattern 1, 4, 9, 16, 25 ... are ______.
Express 81 as the sum of first nine consecutive odd numbers.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
