हिंदी

The solution of the differential equation cosx siny dx + sinx cosy dy = 0 is ______.

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प्रश्न

The solution of the differential equation cosx siny dx + sinx cosy dy = 0 is ______.

विकल्प

  • `sinx/siny` = c

  • sinx siny = c

  • sinx + siny = c

  • cosx cosy = c

MCQ
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उत्तर

The solution of the differential equation cosx siny dx + sinx cosy dy = 0 is sinx siny = c.

Explanation:

The given differential equation is cosx siny dx + sinx cosy dy = 0

⇒ sinx cosy dy = – cosx siny dx

⇒ `cosy/siny "d"y = - cosx/sinx "d"x`

⇒ coty dy = – cotx dx

Integrating both sides, we have

⇒ `int coty  "d"y = - int cot x  "d"x`

⇒ `log|sin y| = - log|sin| + log"c"`

⇒ `log|siny| + log|sinx| = log"c"`

⇒ `log|siny . sin x| = log"c"`

⇒ sinx siny = c

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९८]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 57 | पृष्ठ १९८

वीडियो ट्यूटोरियलVIEW ALL [2]

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