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The Sides of an Equilateral Triangle Are Increasing at the Rate of 2 Cm/Sec. How Far is the Area Increasing When the Side is 10 Cms?

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प्रश्न

The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. How far is the area increasing when the side is 10 cms?

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उत्तर

\[\text { Let x be the side andAbe the area of the equilateral triangle at any timet.Then, }\]
\[A = \frac{\sqrt{3}}{4} x^2 \]
\[ \Rightarrow \frac{dA}{dt} = 2 \times \frac{\sqrt{3}}{4} x^{} \frac{dx}{dt}\]
\[\Rightarrow\frac{dA}{dt}=\frac{\sqrt{3}}{2}\times2\times10\]
\[\Rightarrow\frac{dA}{dt}=10\sqrt{3} \text {cm}^2 /sec\]

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अध्याय 12: Derivative as a Rate Measurer - Exercise 13.3 [पृष्ठ २४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 12 Derivative as a Rate Measurer
Exercise 13.3 | Q 3 | पृष्ठ २४

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