Advertisements
Advertisements
प्रश्न
The magnetic intensity H at the centre of a long solenoid carrying a current of 2.0 A, is found to be 1500 A m−1. Find the number of turns per centimetre of the solenoid.
Advertisements
उत्तर
Here,
Current in the solenoid, I = 2 A
Magnetic intensity at the centre of long solenoid, H = 1500 Am−1
Magnetic field produced by a solenoid (B) is given by,
B = µ0ni ............(1)
Here, n = number of turns per unit length
i = electric current through the solenoid
Also, the relation between magnetic field strength (B) and magnetic intensity (H) is given by,
\[H=\frac{B}{\mu_0}.............(2)\]
From equations (1) and (2), we get:-
H = ni
⇒ 1500 A/m = n × 2
⇒ n = 750 turns/meter
⇒ n = 7.5 turns/cm
APPEARS IN
संबंधित प्रश्न
The magnetic moment of a magnet of dimensions 5 cm × 2.5 cm × 1.25 cm is 3 Am2. Calculate the intensity of magnetization.
Mark out the correct options.
(a) Diamagnetism occurs in all materials.
(b) Diamagnetism results from the partial alignment of permanent magnetic moment.
(c) The magnetising field intensity, H, is always zero in free space.
(d) The magnetic field of induced magnetic moment is opposite the applied field.
Assume that each iron atom has a permanent magnetic moment equal to 2 Bohr magnetons (1 Bohr magneton equals 9.27 × 10−24 A m2). The density of atoms in iron is 8.52 × 1028 atoms m−3. (a) Find the maximum magnetisation I in a long cylinder of iron (b) Find the maximum magnetic field B on the axis inside the cylinder.
Explain the magnetization of a material.
An electron moves in a circular orbit with uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is [µ0 = permeability of free space, e = electronic charge]
A solenoid has core of a material with relative permeability 500 and its windings carry a current of 2 A. The number of turns of the solenoid is 500 per metre. The magnetization of the material is ______.
Two parallel wires of equal lengths are separated by a distance of 3m from each other. The currents flowing through first and second wire is 3A and 4.5A respectively in opposite directions. The resultant magnetic field at the mid-point of both wire is (µ0 = permeability of free space).
What is the magnetization of a bar magnet having length 5 cm and area of cross section 2 cm2? (M = 1 Am2)
The magnetic susceptibility of paramagnetic materials is ____________.
The relative magnetic permeability (`mu_"r"`) of a substance is related to its susceptibility (`chi`) as ____________.
The variation of intensity of magnetization (I) and applied magnetic field intensity (H) for three magnetic materials A, B, C are shown in the graph. The material A is ____________.
The magnetic moment produced in a substance of mass 5 gram is 6 x 10-7 Am2 If its density is 5 g/cm3, then intensity of magnetization in `"A"/"m"` will be ____________.
Magnetic lines of force due to a bar magnet do not intersect because ______.
A magnetic needle of magnetic moment 6.7 × 10–2 Am2 and moment of inertia 7.5 × 10–6 kg m2 is performing simple harmonic oscillations in a magnetic field of 0.01 T. Time taken for 10 complete oscillations is ______.
State unit and dimensions of Magnetic susceptibility.
For a medium of permeability µ, its magnetic susceptibility x is [µ 0 = permeability of vacuum]
The magnetic susceptibility of iron is 5499. The relative permeability of iron will be ______.
