हिंदी

The figure, given below, shows a trapezium ABCD. M and N are the mid-point of the non-parallel sides AD and BC respectively. Find: i. MN, if AB = 11 cm and DC = 8 cm.

Advertisements
Advertisements

प्रश्न

The figure, given below, shows a trapezium ABCD. M and N are the mid-point of the non-parallel sides AD and BC respectively. Find: 

  1. MN, if AB = 11 cm and DC = 8 cm.
  2. AB, if DC = 20 cm and MN = 27 cm.
  3. DC, if MN = 15 cm and AB = 23 cm.
योग
Advertisements

उत्तर

Let we draw a diagonal AC as shown in the figure below,

(i) Given that AB = 11 cm, CD = 8 cm

From triangle ABC

ON = `[1]/[2]` AB

= `[1]/[2]` × 11

= 5.5 cm

From triangle ACD

OM = `[1]/[2]` CD

=`[1]/[2]` × 8

= 4 cm

Hence, MN = OM + ON

= (4 + 5.5)

= 9.5 cm

(ii) Given that CD = 20 cm, MN = 27 cm

From triangle ACD

OM = `[1]/[2]` CD

= `[1]/[2]` × 20

= 10 cm

Therefore, ON = 27 - 10 = 17 cm

From triangle ABC

AB = 2ON

= 2 × 17

= 34 cm

(iii) Given that AB = 23 cm, MN = 15 cm

From triangle ABC

ON =`[1]/[2]` AB

=`[1]/[2]` × 23

= 11.5 cm

OM = 15 - 11.5

OM = 3.5 cm

From triangle ACD

CD = 2OM

= 2 × 3.5

CD = 7 cm

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Mid-point and Its Converse [ Including Intercept Theorem] - Exercise 12 (A) [पृष्ठ १५०]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 12 Mid-point and Its Converse [ Including Intercept Theorem]
Exercise 12 (A) | Q 5 | पृष्ठ १५०

संबंधित प्रश्न

In below fig. ABCD is a parallelogram and E is the mid-point of side B If DE and AB when produced meet at F, prove that AF = 2AB.


Fill in the blank to make the following statement correct:

The figure formed by joining the mid-points of consecutive sides of a quadrilateral is           


D, E, and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC.

Prove that ΔDEF is also isosceles.


In triangle ABC, P is the mid-point of side BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R.
Prove that : (i) AP = 2AR
                   (ii) BC = 4QR


If the quadrilateral formed by joining the mid-points of the adjacent sides of quadrilateral ABCD is a rectangle,
show that the diagonals AC and BD intersect at the right angle.


In ΔABC, D, E, F are the midpoints of BC, CA and AB respectively. Find DE, if AB = 8 cm


ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: 2EF = BD.


In a parallelogram ABCD, E and F are the midpoints of the sides AB and CD respectively. The line segments AF and BF meet the line segments DE and CE at points G and H respectively Prove that: EGFH is a parallelogram.


In ΔABC, the medians BE and CD are produced to the points P and Q respectively such that BE = EP and CD = DQ. Prove that: A is the mid-point of PQ.


In the given figure, PS = 3RS. M is the midpoint of QR. If TR || MN || QP, then prove that:

RT = `(1)/(3)"PQ"`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×