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The Electric Current in a Charging R−C Circuit is Given by I = I0 E−T/Rc Where I0, R and C Are Constant Parameters of the Circuit and T is Time. - Physics

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प्रश्न

The electric current in a charging R−C circuit is given by i = i0 e−t/RC where i0, R and C are constant parameters of the circuit and t is time. Find the rate of change of current at (a) t = 0, (b) t = RC, (c) t = 10 RC.

योग
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उत्तर

Given: i = i0 e−t/RC
∴ Rate of change of current
\[= \frac{di}{dt}\]
\[= i_0 \left( \frac{- 1}{RC} \right) e^{- t/RC}\]
\[= \frac{- i_0}{RC} \times e^{- t/RC}\]
On applying the conditions given in the questions, we get:
(a) At \[t = 0, \frac{di}{dt} = \frac{- i_0}{RC} \times e^0 = \frac{- i_0}{RC}\]
(b) At  \[t = RC, \frac{di}{dt} = \frac{- i_0}{RC} \times e^{- 1} = \frac{- i_0}{RCe}\]
(c) At \[t = 10 RC, \frac{dt}{di} = \frac{- i_0}{RC} \times e^{10}\] \[= \frac{- i_0}{RC e^{10}}\]

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अध्याय 2: Physics and Mathematics - Exercise [पृष्ठ २९]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 2 Physics and Mathematics
Exercise | Q 22 | पृष्ठ २९

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