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प्रश्न
The distance of the point P(–6, 8) from the origin is ______.
विकल्प
8
`2sqrt(7)`
10
6
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उत्तर
The distance of the point P(–6, 8) from the origin is 10.
Explanation:
Distance formula: d2 = (x2 – x1)2 + (y2 – y1)2
According to the question,
We have,
x1 = – 6, x2 = 0
y1 = 8, y2 = 0
d2 = [0 – (– 6)]2 + [0 – 8]2
d = `sqrt((0 - (-6))^2 + (0 - 8)^2`
d = `sqrt((6)^2 + (-8)^2`
d = `sqrt(36 + 64)`
d = `sqrt(100)`
d = 10
Therefore, the distance between P(–6, 8) and origin O(0, 0) is 10.
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By distance formula,
PQ = `sqrt(square + (y_2 - y_1)^2`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(125)`
= `5sqrt(5)`
