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The Current in the Forward Bias is Known to Be More (~Ma) than the Current in the Reverse Bias (~μA). What is the Reason, Then, to Operate the Photodiode in Reverse Bias? - Physics

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प्रश्न

The current in the forward bias is known to be more (~mA) than the current in the reverse bias (~μA). What is the reason, then, to operate the photodiode in reverse bias?

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उत्तर

The photodiode always work under reverse biasing conditions although the current produced is less. This is because in reverse bias, the width of the depletion layer increases which reduces the capacitance across the junction, thereby increasing response time. The sensitivity of a photodiode is thus very high, a property that is certainly desired.

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2011-2012 (March) Delhi Set 1

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

With the help of a neat circuit diagram, explain the working of a photodiode. 


Meeta's father was driving her to school. At the traffic signal, she noticed that each traffic light was made of many tiny lights instead of a single bulb. When Meeta asked this question to her father, he explained the reason for this.

Answer the following questions based on above information:

(i) What were the values displayed by Meeta and her father?

(ii) What answer did Meeta's father give?

(iii) What are the tiny lights in traffic signals called and how do these operate?


Describe, with the help of a circuit diagram, the working of a photodiode.


Write briefly the important processes that occur during the formation of p−n junction. With the help of necessary diagrams, explain the term 'barrier potential'.


Draw the circuit arrangement for studying the V-I characteristics of a p-n junction diode in reverse bias. Plot the V-I characteristics in this case.


If the resistance R1 is increased (Figure), how will the readings of the ammeter and voltmeter change?


Read the following paragraph and answer the questions.

LED is a heavily doped P-N junction which under forward bias emits spontaneous radiation. When it is forward-biased, due to recombination of holes and electrons at the junction, energy is released in the form of photons. In the case of Si and Ge diode, the energy released in recombination lies in the infrared region. LEDs that can emit red, yellow, orange, green and blue light are commercially available. The semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8 eV. The compound semiconductor Gallium Arsenide – Phosphide is used for making LEDs of different colours.


LEDs of different kinds

  1. Why are LEDs made of compound semiconductor and not of elemental semiconductors?
  2. What should be the order of bandgap of an LED, if it is required to emit light in the visible range?
  3. A student connects the blue coloured LED as shown in the figure. The LED did not glow when switch S is closed. Explain why?

    OR
    iii. Draw V-I characteristic of a p-n junction diode in
    (i) forward bias and (ii) reverse bias

Draw solar cells of I-V characteristics.


What energy conversion takes place in a solar cell?


  1. For a solar-cell the I-V characteristics lies in the (IV) quadrant of the given graph.
  2. In a reverse biased p-n junction diode, the current measured in (μA), is due to majority charge carriers.

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