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The Coefficient of Volume Expansion of Glycerin is 49 × 10–5 K–1. What is the Fractional Change in Its Density for a 30 °C Rise in Temperature

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प्रश्न

The coefficient of volume expansion of glycerin is 49 × 10–5 K–1. What is the fractional change in its density for a 30 °C rise in temperature?

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उत्तर १

Coefficient of volume expansion of glycerin, αV = 49 × 10–5 K–1

Rise in temperature, Δ= 30°C

Fractional change in its volume =`(triangle V)/V`

This change is related with the change in temperature as:

`(triangle V)/V = alpha_V triangle T`

`V_(T_2) - V_(T_1) = V_(T_1) alpha_V triangle T`

`m/rho_(T_2) - m/rho_(T_1) = m/rho_(T_1) alpha_1 triangleT`

Where,

m = Mass of glycerine

`rho_(T_1)` = Initial density at `T_1`

`rho_(T_2)` = Final density at `T_2`

`(rho_(T_1) - rho_(T_2))/rho_(T_2) = alpha_1 triangle T`

Where

`(rho_(T_1) - rho_(T_2_))/(rho_T_2)` =  = Fractional change in density

∴Fractional change in the density of glycerin = 49 ×10–5 × 30 = 1.47 × 10–2

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उत्तर २

Here `gamma= 49 xx 10^(-5) ""^@C^(-1)`, `triangle T  = 30 ""^@C`

As` V = V + triangle V = V(1+gamma triangle T)`

`V' = V(1+49xx10^(-5)xx30) = 1.0147 V`

Since `rho = m/V, rho^n = m/(V') = m/1.0147V = 0.9855 rho`

Fractional change in density = `(rho - rho')/rho`

`= (rho - 0.9855 rho)/rho = 0.0145`

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अध्याय 10: Thermal Properties of Matter - Exercises [पृष्ठ २९५]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 11
अध्याय 10 Thermal Properties of Matter
Exercises | Q 11 | पृष्ठ २९५

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