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प्रश्न
State Fleming’s left-hand rule.
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उत्तर
Hold the forefinger, the centre finger and the thumb of your left hand at right angles to one another. Adjust your hand in such a way that the forefinger points in the direction of the magnetic field and the centre finger points in the direction of the current in the conductor; then the direction in which the thumb points gives the direction of motion of the conductor.
संबंधित प्रश्न
A positively-charged particle (alpha-particle) projected towards west is deflected towards north by a magnetic field. The direction of magnetic field is ______.
Observe the following figure:
If the current in the coil A is changed, will some current be induced in the coil B? Explain.
What concealed do you get from the observation that a current-carrying wire deflects a compass needle placed near it?
Name and state the rule to determine the direction of magnetic field around a straight current-carrying conductor.
The front face of a circular wire carrying current behaves like a north pole. The direction of current in this face of circular wire is:
(a) clockwise
(b) downwards
(c) anticlockwise
(d) upwards
A coil ABCD mounted on an axle is placed between the poles N and S of a permanent magnet as shown in Figure.
- In which direction will the coil begin to rotate when current is passed through the coil in direction ABCD by connecting a battery at the ends A and D of the coil?
- Why is a commutator necessary for continuous rotation of the coil?
- Complete the diagram with commutator, etc. for the flow of current in the coil?
State Fleming’s left-hand rule.
A flat coil ABCD is freely suspended between the pole of a U-shaped permanent magnet with the plane of coil parallel to the magnetic field.
When will coil come to rest?
State under what conditions force acting on a current carrying conductor which is freely suspended in a magnetic field can be Zero.
The diagram below shows a free conductor AB is kept in a magnetic field and is carrying current from A to B. (To avoid confusion complete path of the circuit is not shown) The direction of the force experienced by the conductor will be:
