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Solve the following equation for x, y ∈ R: 2x + i9y (2 + i) = xi7 + 10i16 - Mathematics and Statistics

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प्रश्न

Solve the following equation for x, y ∈ R:

2x + i9y (2 + i) = xi7 + 10i16

योग
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उत्तर

2x + i9y (2 + i) = xi7 +10i16 

i9 = i8 x i = (i2)4i = (– 1)4i = i

i7 = i6 x i = (i2)3i = (–1)3i = – i

i16 = (i2)8 = (– 1)8 = 1

∴ given equation becomes

2x + iy(2 + i) = – xi + 10

∴ 2x + 2iy + i2y = – xi + 10

∴ 2x + 2iy – y = – xi + 10  ...[∵ i2 = – 1]

∴ 2x + 2iy – y + xi – 10 = 0

∴ (2x – y – 10) + (x + 2y)i = 0

∴ (2x – y) + (x + 2y)i = 10 + 0i

Equating the real and imaginary parts separately, we get,

2x – y = 10        ...(1)

and x + 2y = 0      ...(2)

Multiplying equation (1) by 2, we get, 4x – 2y = 20

Adding this equation with equation (2), we get,

5x = 20

∴ x = 4

∴ from (2), 4 + 2y = 0

∴ 2y = – 4

∴ y = – 2

Hence, x = 4, y = – 2.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Complex Numbers - Miscellaneous Exercise 1.2 [पृष्ठ २२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 1 Complex Numbers
Miscellaneous Exercise 1.2 | Q II. (2) (iv) | पृष्ठ २२

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