हिंदी

Show that 1 + i10 + i20 + i30 is a real number.

Advertisements
Advertisements

प्रश्न

Show that 1 + i10 + i20 + i30 is a real number.

योग
Advertisements

उत्तर

1 + i10 + i20 + i30 
= 1 + (i4)2 .i2 + (i4)5 + (i4)7 .i2
= 1 + (1)2 (– 1 ) + (1)5 + (1)7 (– 1)   ...[∵ i4 = 1, i2 = –1]
= 1 – 1 + 1 –1
= 0, which is a real number.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Complex Numbers - EXERCISE 3.1 [पृष्ठ ३८]

APPEARS IN

बालभारती Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 3 Complex Numbers
EXERCISE 3.1 | Q 5) | पृष्ठ ३८

संबंधित प्रश्न

Find the multiplicative inverse of the complex number.

`sqrt5 + 3i`


Find the value of: x3 –  x2 + x + 46, if x = 2 + 3i


Simplify the following and express in the form a + ib:

`(5 + 7"i")/(4 + 3"i") + (5 + 7"i")/(4 - 3"i")`


Write the conjugates of the following complex number:

3 – i


Write the conjugates of the following complex number:

cosθ + i sinθ


If a = `(-1 + sqrt(3)"i")/2`, b = `(-1 - sqrt(3)"i")/2` then show that a2 = b and b2 = a


Answer the following:

Simplify the following and express in the form a + ib:

(2i3)2 


If z1, z2, z3 are complex numbers such that `|z_1| = |z_2| = |z_3| = |1/z_1 + 1/z_2 + 1/z_3|` = 1, then find the value of |z1 + z2 + z3|.


State true or false for the following:

The points representing the complex number z for which |z + 1| < |z − 1| lies in the interior of a circle.


What is the reciprocal of `3 + sqrt(7)i`.


1 + i2 + i4 + i6 + ... + i2n is ______.


If `((1 + i)/(1 - i))^3 - ((1 - i)/(1 + i))^3` = x + iy, then find (x, y).


If z1 and z2 are complex numbers such that z1 + z2 is a real number, then z2 = ______.


Find `|(1 + i) ((2 + i))/((3 + i))|`.


Which of the following is correct for any two complex numbers z1 and z2?


If z is a complex number, then ______.


Let `(-2 - 1/3i)^2 = (x + iy)/9 (i = sqrt(-1))`, where x and y are real numbers, then x – y equals to ______.


Simplify the following and express in the form a + ib.

`(3i^5 + 2i^7 + i^9) / (i^6 + 2i^8 + 3i^18)`


Simplify the following and express in the form a + ib.

`(3i^5+2i^7+i^9)/(i^6+2i^8+3i^18)`


Show that `(-1 + sqrt3i)^3` is a real number.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×